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A heterozygote means different-joined
a homozygote means same-joined
so lets look at this cross. (parent genotype are Bold and italics)
---B----b
B | BB | Bb |
--------------------
B | BB | Bb |
We see that 2 "joined" zygotes are BB and 2 are Bb
SO by definition 2 combinations produce a heterozygote "Bb"
and 2 produce a homozygote "BB"
Wiki User
∙ 12y ago
Wiki User
∙ 9y agoThe offspring will be heterozygous Bb.
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What are dominant and recessive alleles with examples?
dominant alleles will always overrule recessive alleles. So if you have any dominant allele in the phnotype or geneotype, the dominant trait will be expressed. For example, since black fur is dominant to brown fur on mice, if two black mice mate, at least part of their offspring will have black fur. If they are heterozygous for black, though, that's when a brown mouse offspring may be possible, but there would always be more black offspring than brown offspring. parents offspring (4) Bb x Bb --> BB, Bb, Bb, bb BB x Bb --> BB, BB, Bb, Bb BB x BB --> BB, BB, BB, BB BB x bb --> Bb, Bb, Bb, Bb Bb x bb --> Bb, Bb, bb, bb anything with a capital B would be black while "bb" is the only brown.
In a BB x bb cross?
in a Bb x bb cross?
What is the generation of the offspring of a cross between parents that are pure for a given trait?
The first generation cross, known as F1 (filial 1), for homozygous (purebred) parents will be heterozygous - have one allele of each of their parents' traits. For example, the cross BB X bb would result in an F1 genotype of Bb.
What is the genotypes of offspring from the following cross AABB x aabb?
You make a box with 4 boxes in it and then you plug in the parents on the top and the side, which is the BBxBb, and match up the alleles (the letters) like coordinates in a graph. BBBBBBBBbBbb
In the cross BB x bb the percent of offspring in the F1 generation that will have the same genotype as their parents is?
answer is 0%
How do you solve the phenotype and genotype of a punnet square?
Well it depends on how many of each that you have. Let's start simple. Let's say your mom has brown eyes which is a dominant gene meaning it has a capital B and your dad has blue eyes which is a recessive gene which means it has a lower case b. So mom can either be Bb or BB in order to have brown eyes, but dad is definitely bb because he has blue eyes. So let's just say mom is BB. So for this punnet square you would only need four squares. On the top two you put a B and a B on each square which stands for mom's gene. On the side of the square you put b and a b on each of the two squares which stand for dad's genes. Now all you do is write the new gene in each box. For the top left hand box you would write bB since that b is what dad gives and B is what mom gives. For the top right hand box you write bB again since that is what mom and dad is giving off. Then you do the bottom two squares the same way. Now let's say we want to add height to this. Dad is tall so he is T. Mom is short so she is t. You use the punnet squares again in the exact same way. Place mom's genes on the top and dad are on the bottom. You can also figure out probabilities of genotypes and phenotypes by doing fractions. Someone who is BB or bb is homozygous (means same) for that gene. Someone who is Bb is heterozygous (means opposite). Anyone who is homozygous dominant (BB) that mates with a homozygous recessive (bb) person will result in a punnet square with ¼ Bb, ¼ Bb, ¼ Bb, and ¼ Bb meaning that all of their children will have brown eyes. Anyone who is homozygous dominant (BB) that mates with a heterozygous (Bb) will have ¼ BB, ¼ Bb, ¼ Bb, and ¼ bb. So ¾ of the children will be brown eyed and ¼ blue eyed. If you have heterozygous (Bb) mate with a homozygous (bb) you will have ½ Bb and ½ bb. Using fractions would be easier if you can't get the punnet squares correct.Below is an example of how to do more than one trait.Ex. In peas, tall (D) is dominant to dwarf (d) and yellow cotyledons (G) is dominant to green (g). If a tall, heterozygous pea plant with green cotyledons is crossed with a dwarf pea plant heterozygous for yellow cotyledons, what will be the phenotypic results in the progeny?Ddgg x ddGgDg dg x dG dgdGdgDgDdGgDdggdgddGgddgg½ D ½ d 1g ½ DgProbability of tall ½Probability of short ½Yellow ½Green ½Tall and yellow (1/2 x ½)= ¼Tall and green (1/2 x ½)= ¼Dwarf and yellow (1/2 x ½)= ¼Dwarf and green (1/2 x ½)= ¼
What are dominant and recessive alleles with examples?
dominant alleles will always overrule recessive alleles. So if you have any dominant allele in the phnotype or geneotype, the dominant trait will be expressed. For example, since black fur is dominant to brown fur on mice, if two black mice mate, at least part of their offspring will have black fur. If they are heterozygous for black, though, that's when a brown mouse offspring may be possible, but there would always be more black offspring than brown offspring. parents offspring (4) Bb x Bb --> BB, Bb, Bb, bb BB x Bb --> BB, BB, Bb, Bb BB x BB --> BB, BB, BB, BB BB x bb --> Bb, Bb, Bb, Bb Bb x bb --> Bb, Bb, bb, bb anything with a capital B would be black while "bb" is the only brown.
In a BB x bb cross?
in a Bb x bb cross?
What is the generation of the offspring of a cross between parents that are pure for a given trait?
The first generation cross, known as F1 (filial 1), for homozygous (purebred) parents will be heterozygous - have one allele of each of their parents' traits. For example, the cross BB X bb would result in an F1 genotype of Bb.
A homozygous dominant black bear is mated with a recessive brown bear what phenotype will probably result in the offspring of the two bears?
Phenotype: Black Bear x Brown Bear Genotype: BB x bb Possible gametes: B B b b Possible B B crosses: b Bb Bb b Bb Bb Phenotype of offspring: Only Black bears
If a homozygous dominant is crossed with a homozygous recessive for a given trait the offspring will be?
The phenotype will show the dominant trait. All dominant traits mask recessive ones; If the genotype is heterozygous (One dominant and one recessive) the organism's phenotype will be dominant.
What is an example of two heterozygous parents?
The possible genotypes of parents who are heterozygous would be found using a punnet square. The outcome would be 50 percent heterozygous dominant, 25 percent homozygous dominant, and 25 percent homozygous recessive.
What is the genotypes of offspring from the following cross AABB x aabb?
You make a box with 4 boxes in it and then you plug in the parents on the top and the side, which is the BBxBb, and match up the alleles (the letters) like coordinates in a graph. BBBBBBBBbBbb
Why isn't the dominant gene's trait always the most common?
Statistical mating between mom and dad. Bb X Bb 1/4 of the time, statistically, you will get progeny with the alleles bb, the homozygous recessive traits.
If two black cows have a baby cow what color will that cow be?
Two cows cannot mate to get a calf (or "cow" in this instance). You have to have a BULL and a cow to get a baby calf. Just like you gotta have a Mom and a Dad to "make" you.Now back to the question. If the bull is black and the cow is black, there is a high chance that you will get a black calf. However, let's increase the complexity and throw in a bit of genetic terminology in here.Let B = black and b = red. Black is always homozygous or dominant to red in cattle.If both the sire and dam is heterozygous black (Bb x Bb) , there is a 25% chance that you will get a red calf (bb). But if both parents are homozygous for black, there is a 100% chance that the calf will not be red, but instead, homozygous black (BB). If either one of the parents are heterozygous black, the calf still has a 100% chance that it will be black, phenotypically. But, genotypically, the calf has a 25% chance of being heterozygous black. A heterozygous black calf, no matter if it grows into a cow or a bull (depending on the calf's sex), will have a 25% chance of giving birth to or siring red calves if crossed with a heterozygous black bull or cow or a a 75% chance of siring a red calf with a red bull or cow.
What does genotypic ratio mean?
genotype means genetic make up. it can give the information about the parents wether they were homozygous or heterzygousAnswer (Improved)A genotypic ratio is the proportion of genotypes found in individuals after a cross. For example, consider a cross between two heterozygous individuals for trait A: Aa X AaThe result is a 1:2:1 ratio for the genotypes AA, Aa, and AA respectively. Put another way, if the parents had 100 offspring, 25 would be expected to have the genotype AA, 50 the genotype Aa and 25 the genotype AA.This is hard Good Luck
In the cross BB x bb the percent of offspring in the F1 generation that will have the same genotype as their parents is?
answer is 0%
