in a Bb x bb cross?
You make a box with 4 boxes in it and then you plug in the parents on the top and the side, which is the BBxBb, and match up the alleles (the letters) like coordinates in a graph. BBBBBBBBbBbb
In the cross BB x bb, all offspring in the F1 generation will have the genotype Bb, as they inherit one allele from each parent. None of the offspring will have the same genotype as either parent.
A heterozygote means different-joineda homozygote means same-joinedso lets look at this cross. (parent genotype are Bold and italics)---B----bB | BB | Bb |--------------------B | BB | Bb |We see that 2 "joined" zygotes are BB and 2 are BbSO by definition 2 combinations produce a heterozygote "Bb"and 2 produce a homozygote "BB"
The first generation cross, known as F1 (filial 1), for homozygous (purebred) parents will be heterozygous - have one allele of each of their parents' traits. For example, the cross BB X bb would result in an F1 genotype of Bb.
dominant alleles will always overrule recessive alleles. So if you have any dominant allele in the phnotype or geneotype, the dominant trait will be expressed. For example, since black fur is dominant to brown fur on mice, if two black mice mate, at least part of their offspring will have black fur. If they are heterozygous for black, though, that's when a brown mouse offspring may be possible, but there would always be more black offspring than brown offspring. parents offspring (4) Bb x Bb --> BB, Bb, Bb, bb BB x Bb --> BB, BB, Bb, Bb BB x BB --> BB, BB, BB, BB BB x bb --> Bb, Bb, Bb, Bb Bb x bb --> Bb, Bb, bb, bb anything with a capital B would be black while "bb" is the only brown.
You make a box with 4 boxes in it and then you plug in the parents on the top and the side, which is the BBxBb, and match up the alleles (the letters) like coordinates in a graph. BBBBBBBBbBbb
In the cross BB x bb, all offspring in the F1 generation will have the genotype Bb, as they inherit one allele from each parent. None of the offspring will have the same genotype as either parent.
To determine the probability of different offspring from the cross of genotypes BB, Bb, and bb, we first need to clarify the specific cross being made. If we are crossing BB (homozygous dominant) with Bb (heterozygous), the potential offspring would be 50% BB and 50% Bb. If we then cross this with bb (homozygous recessive), the resulting offspring would be 50% Bb and 50% bb. Thus, the probabilities for the offspring would be 50% Bb and 50% bb.
A heterozygote means different-joineda homozygote means same-joinedso lets look at this cross. (parent genotype are Bold and italics)---B----bB | BB | Bb |--------------------B | BB | Bb |We see that 2 "joined" zygotes are BB and 2 are BbSO by definition 2 combinations produce a heterozygote "Bb"and 2 produce a homozygote "BB"
BB. Bb Bb. bb
The Punnett square for crossing two heterozygous dogs (Bb x Bb) would result in a 25% chance of offspring with homozygous dominant black fur (BB), a 50% chance of offspring with heterozygous black fur (Bb), and a 25% chance of offspring with homozygous recessive brown fur (bb).
The chance of a particular trait being inherited. For each trait there are several alleles, some are dominant and others recessive, for example brown eyes are dominant over blue. The recessive phenotype can only have a genotype with both recessive alleles eg. bb The dominant phenotype can have a genotype with both dominant alleles eg. BB or one of each eg. Bb A punnet square shows the likelihood of a phenotype being inherited from given genotypes, alleles etc... BB and Bb makes BB BB Bb Bb All offspring will have the dominant phenotype (BB or Bb) eg. brown eyes Bb and Bb makes BB Bb Bb bb One in four of the offspring will have the recessive phenotype (bb) eg. blue eyes
D-C-B D-C-B D-D-D-D C-C-C-C D-C-B it just takes some practice good luck!
Bb, Bb, C, Bb, Eb, D Bb, Bb, C, Bb, F, Eb Bb, Bb, Bb(up an octave), G, Eb, D, C Ab, Ab, G, Eb, F, Eb
Bb Bb C Bb Eb D Bb Bb C Bb F Eb Bb Bb Bb G Eb D C Ab Ab G Eb F Eb
a, a, a, a, a, a, a, c, f, g, a, bb, bb, bb, bb, bb, a, a, a, a, g, g, g, a, g, c a, a, a, a, a, a, a, c, f, g, a, bb, bb, bb, bb, bb, a, a, a, a, c, c, bb, g, f. The key is F Major
A test cross with a homozygous recessive guinea pig (bb) would reveal the genotype of the black guinea pig. If all offspring are black, then the black guinea pig is most likely homozygous dominant (BB). If both black and white offspring are produced, then the black guinea pig is likely heterozygous (Bb).