0
In probability theory, it could be 0.78
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What is the theory of kelvin's double bridge experiment?
Theory: - Kelvin's bridge is a modification of whetstone's bridge and always used in measurement of low resistance. It uses two sets of ratio arms and the four terminal resistances for the low resistance consider the ckt. As shown in fig. The first set of ratio P and Q. The second set of ratio arms are p and q is used to connected to galvanometer to a pt d at an Approx. potential between points m and n to eliminate the effects of connecting lead of resistance r between the known std. resistance 's' and unknown resistance R .The ratio P/Q is made equal to p/q. under balanced condition there is no current flowing through galvanometer which means voltage drop between a and b, Eab equal to the voltage drop between a and c, Eamd. Now Ead=P/P+Q ; Eab=I[R+S+[(p+q)r/p+q+r]] ------------(1) Eamd= I[R+ p/p+q[ (p+q)r/p+q+r]] ---------------------(2) For zero deflection->Eac=Ead [ P/P+Q]I[R+S+{(p+q)r/p+q+r}]=I[R+pr/p+q+r] ----(3) Now, if P/Q=p/q Then equation… (3) becomes R=P/Q=S ------------------------------------------------------(4) Equation (4) is the usual working equation. For the Kelvin's Double Bridge .It indicates the resistance of connecting lead r. It has no effect on measurement provided that the two sets of ratio arms have equal ratios. Equation (3) is useful however as it shows the error that is introduced in case the ratios are not exactly equal. It indicates that it is desirable to keep r as small as possible in order to minimize the error in case there is a diff. between the ratio P/Q and p/q. R=P/QS
What is the value of focal length of plane mirror?
Infinity.because the distance of object from mirror"p" and the distance from image to mirror"q" are equal,so by using formula1/f=1/p+1/qwe can find the answeras the image of plane mirror is virtual,so"q" is taken negative,so putting values1/f=1/p-1/p(bcz p=q)1/f=0f=1/0and any thing divided by zero is infinity.hope this helps
What are the four magic triangles in physics?
I don't know if this is what ur looking for but this is what I have Resistance or "Ohm's Law" V R I V=volts R=ohm or resistance I=Amperes Power E P t E=joules P=watts t= time in sec. Potential Difference E V Q E=joules V=volts Q=coulombs Current Q I t Q=coulombs I=Amperes t= time in sec.
Concave mirror with a focal length of 10cm creates a real image 30cm away on in princial axis how far from the mirror is its coresponding object?
1/f=1/p + 1/q f=focal length p=actual length of object q=imagine length plug&chug
How do you move on QWOP?
To move on QWOP you use Q, W, O, P. each one is a different part of the leg
If p q and q r then p r. Converse statement B.A syllogism C.Contrapositive statement D.Inverse statement?
Converse: If p r then p q and q rContrapositive: If not p r then not (p q and q r) = If not p r then not p q or not q r Inverse: If not p q and q r then not p r = If not p q or not q r then not p r
What is the sum or difference of p and q?
The sum of p and q means (p+q). The difference of p and q means (p-q).
What is qĀ²-pĀ² divided by q-p?
q + p
What is the truth table for p arrow q?
Not sure I can do a table here but: P True, Q True then P -> Q True P True, Q False then P -> Q False P False, Q True then P -> Q True P False, Q False then P -> Q True It is the same as not(P) OR Q
If p is 50 of q then what percent of p is q?
If p = 50 of q then q is 2% of p.
How do you write the negation of if and then?
If p then q is represented as p -> q Negation of "if p then q" is represented as ~(p -> q)
Simplify pp - q - q q - p?
p-q
What does p over q mean in algebra?
P! / q!(p-q)!
Why does multiplication or division with a negative number yield a negative answer?
The assertion in the question is not always true. Multiplying (or dividing) 0 by a negative number does not yields 0, not a negative answer.Leaving that blunder aside, let p and q be positive numbers so that p*q is a positive number.Thenp*q + p*(-q) = p*[q + (-q)] = p*[q - q] = p*0 = 0that is p*q + p*(-q) = 0Thus p*(-q) is the additive opposite of p*q, and so, since p*q is positive, p*(-q) must be negative.A similar argument works for division.
How does every rational number have an additive inverse?
By definition, every rational number x can be expressed as a ratio p/q where p and q are integers and q is not zero. Consider -p/q. Then by the properties of integers, -p is an integer and is the additive inverse of p. Therefore p + (-p) = 0Then p/q + (-p/q) = [p + (-p)] /q = 0/q.Also, -p/q is a ratio of two integers, with q non-zero and so -p/q is also a rational number. That is, -p/q is the additive inverse of x, expressed as a ratio.
What type of operator can be used to determine whether a specific relationship that exists between two values?
The relational operators: ==, !=, =.p == q; // evaluates true if the value of p and q are equal, false otherwise.p != q; // evaluates true of the value of p and q are not equal, false otherwise.p < q; // evaluates true if the value of p is less than q, false otherwise.p q; // evaluates true if the value of p is greater than q, false otherwise.p >= q; // evaluates true of the value of p is greater than or equal to q, false otherwiseNote that all of these expressions can be expressed logically in terms of the less than operator alone:p == q is the same as NOT (p < q) AND NOT (q < p)p != q is the same as (p < q) OR (q < p)p < q is the same as p < q (obviously)p q is the same as (q < p)p >= q is the same as NOT (p < q)
Where p and q are statements p and q is called what of p and q?
The truth values.
