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Q: If the area of a rectangle is 8 square inches and the length of the rectangle is twice it's width what is the length and width of the rectangle?

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A rectangle with one side that is double the length of the other side can be seen as two squares beside each other, that are half the area of the original rectangle, in this case 18 square inches / 2 = 9 square inches. The side of a square is the square root of the area, in this case the square root of 9 square inches, which is 3 inches. Now think about the rectangle again. What we just counted was the side of a square that made up one half of the rectangle you wanted to calculate the area of. So the shorter side of the rectangle is the same as our square, and the longer side is double the length. So the width of the rectangle is 3 inches, and the length is 2 * 3 inches = 6 inches. Or: Area = length x width (A=lw) Area = 18 (in2) Width = w Length = twice width (2w) 18 = (2w)w 18 = 2w2 9 = w2 3 = w The width is 3 in., the length (2w) is 6 in.

9" x 4"

4

Length of rectangle is 5 inches and its width is 4 inches Check: 2*(5+4) = 18 inches which is its perimeter

A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.

98 square feet

You draw a rectangle that has a diagonal which length is equal to twice the length of the side of the square.

For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.

2 (x + 2x) = 42 x + 2x = 21 3x = 21 Therefore, x = 7 The width of the rectangle is 7 inches. The length of the rectangle is 14 inches.

The question is not quite clear in what's it's asking. Presumably it's asking what is the length and width of the rectangle? Let the length be 2x and the width be x: 2x*x = 18 2x2 = 18 Divide both sides by 2: x2 = 9 Square root both sides: x = 3 Therefore: length = 6 inches and width = 3 inches If it is asking what the width is, and the length is twice the area, then the width would be .5 inches. (L= A*2, L=36) (36*.5=18) (L*W=A)

W=12,l=9 ((9*2)-6=12, 12*9=108)

The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.

The width is 6 cm and the length is 12 cm.

If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.

4 cm

It is: 10 times 5 = 50 square in

Twice (length + width)

Do-it-in-your-head method: Length + width is half the perimeter which is 27 inches; 27 minus 6 is 21 and one-third of 21 is 7 which is the width. (Length = 2 x 7 + 6 = 20)

The rectangle is 12 units by 3 units.

L=16 in W=8 in

Since the perimeter of a rectangle is 2 * length + 2 * width, 2l + 2w = 36 And since the length is twice the width, l = 2w Thus, you substitute 2w into the l in the first equation to get, 2(2w) + 2w = 36 4w + 2w = 36 6w = 36 w = 6 Plug the value of w into the second equation, l = 2(6) This will give you a length of 12. Since the area of rectangle is l * w, we just substitute the values in for length and width, l * w = 6 * 12 = 72 And that would be in square inches of course.

It is: 15 meters by 30 meters

this is a funky question... 8x10 kilometers

The length is 14 cm

you can't, unless the area was an odd number you can't, unless the area was an odd number