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In normal conditions C always Paris with G and A with U in mRNA so in this CAG the anticoodon wil be GUC
The sequence of amino acids (forming a protein) that result from the mRNA strand CAG-AAG-UUC-CUC-UCG-C would be: Glutamine-Threonine-Phenylalanine-Leucine-Serine Each codon must be three bases long - therefore the end of this mRNA sequence 'C' cannot code for an amino acid. There would also need to be a stop codon at the end to complete translation.
Codon is a group of three bases on a DNA molecule, each determining the identity of one amino acid in proteins made by a cell. An example of a codon is the mRNA sequence of AUG.
A codon is three bases long - so this section of mRNA would have 4 codons; UGA-UUC-AGU-AAC.Each codon relates to a specific amino acid (but several codons can code for the same amino acid, for example both UUU and UUC code for the amino acid Phenylalanine).Normally if you have four codons, such as this section of mRNA, the maximum number of amino acids you could have would be four. However, the first codon in this section, UGA, is actually a STOP codon. This means that when the ribosome reaches this codon, no further amino acids will be joined.This means that no amino acids could be coded for with this section of mRNA. (If the order of the codons was reversed, making the STOP codon last, then the answer would be three).
Serine (Ser) amino acid. --> This is response to the above answer. The question is for the anticodon, but the genetic code table is for CODONS. As you know codons and anticodons bind antiparallel to each other. So, the codon for anticodon AGU = ACU. The first base of the anticodon base paris to the 3rd base of the codon (i.e., wobble base). Therefore with this information the anticodon AGU codes for Threonine. I have a graduate degree in Molecular biology.
In normal conditions C always Paris with G and A with U in mRNA so in this CAG the anticoodon wil be GUC
The sequence of amino acids (forming a protein) that result from the mRNA strand CAG-AAG-UUC-CUC-UCG-C would be: Glutamine-Threonine-Phenylalanine-Leucine-Serine Each codon must be three bases long - therefore the end of this mRNA sequence 'C' cannot code for an amino acid. There would also need to be a stop codon at the end to complete translation.
The DNA strand CAT-TAG would produce a complementary mRNA strand of GUA-AUC.
The codon and the anticodon interact with each other via hydrogen bonding, hence both the codon and anticodon are made up of the same number of nucleotides, which is three.
Messenger RNA (mRNA) serves as the primary transcript, and its nucleotide sequence determines the amino acid sequence of proteins. A codon in mRNA comprises of three nucleotides that encode a specific amino acid. For example, the codon for glutamine is CAG (Cytosine, Adenine and Guanine). The most common stop and start codon is TAA and AUG respectively.
3. The opposite three that are located on the codon of an mRNA strand.eg.If mRNA reads CAG UCG AGU Three codonsThen tRNA GUC AGC UCA Three Antiocodons each containing three nitrogenous bases.
Codon is a group of three bases on a DNA molecule, each determining the identity of one amino acid in proteins made by a cell. An example of a codon is the mRNA sequence of AUG.
CAG
Ala -APEX Learning®️ 2021
A codon is three bases long - so this section of mRNA would have 4 codons; UGA-UUC-AGU-AAC.Each codon relates to a specific amino acid (but several codons can code for the same amino acid, for example both UUU and UUC code for the amino acid Phenylalanine).Normally if you have four codons, such as this section of mRNA, the maximum number of amino acids you could have would be four. However, the first codon in this section, UGA, is actually a STOP codon. This means that when the ribosome reaches this codon, no further amino acids will be joined.This means that no amino acids could be coded for with this section of mRNA. (If the order of the codons was reversed, making the STOP codon last, then the answer would be three).
Serine (Ser) amino acid. --> This is response to the above answer. The question is for the anticodon, but the genetic code table is for CODONS. As you know codons and anticodons bind antiparallel to each other. So, the codon for anticodon AGU = ACU. The first base of the anticodon base paris to the 3rd base of the codon (i.e., wobble base). Therefore with this information the anticodon AGU codes for Threonine. I have a graduate degree in Molecular biology.
insertion