0
If the coefficient of friction is 0.20 what force parallel to a 30 degree incline is required to pull a 100 N box up the incline with an acceleration of 2.0 ms2?
Wiki User
∙ 15y agoWant this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
What is the formula for Coefficient of friction?
(Static coefficient of friction) Cf = horizontal force (newtons) required to overcome static resistance / vertical force (newtons) due to objects mass * acceleration due to gravity. Note: Moving friction coefficient is generally less.
What force is required to push an 600N object?
The force required to overcome friction = the coefficient of friction x the reactive force (as in, the force the object exerts on the surface you want to move it over). So, you have to know the coefficient of friction, and simply times it by 600 in this case to know the force required. Oddly, once friction has been overcome, the required force drops slightly to keep it moving.
What kind of friction requires more force to overcome rollingfriction or sliding friction?
Coefficient of rolling friction will always be less than that of sliding friction. Hence more force is required to overcome sliding friction. Because the force = coefficient of friction x normal force (ie weight of the body)
How much work is done if a 10kg mass is moved 5 meters?
The work done is the force multiplied by the distance. You don't have the force in this case; if there is no friction, you would need zero work. If the mass moves is on a flat surface, multiply by the coefficient of friction to get the force required. The coefficient of friction varies for different combinations of materials.The work done is the force multiplied by the distance. You don't have the force in this case; if there is no friction, you would need zero work. If the mass moves is on a flat surface, multiply by the coefficient of friction to get the force required. The coefficient of friction varies for different combinations of materials.The work done is the force multiplied by the distance. You don't have the force in this case; if there is no friction, you would need zero work. If the mass moves is on a flat surface, multiply by the coefficient of friction to get the force required. The coefficient of friction varies for different combinations of materials.The work done is the force multiplied by the distance. You don't have the force in this case; if there is no friction, you would need zero work. If the mass moves is on a flat surface, multiply by the coefficient of friction to get the force required. The coefficient of friction varies for different combinations of materials.
If your pulling 30 lb tire on a lawn what is the estimated weight youre actually pulling because of friction?
the equation for static friction coefficient is:static friction coefficient = force required to break bond / weight of object (tire)you need the friction coefficient between rubber and grass, say its 0.5, this means the force you have to apply to equal the friction force is:0.5 = x / 30x = 0.5 * 30x = 15 lbs fanything greater than 15 lbs f will break the bond and accelerate the tire.notes :1 / moving friction coefficient is usually less than static friction coefficient, so youve less drag once its moving.2 / friction coefficients are never greater than 1.0actually , some friction coefficients do exceed 1.0 , see google / friction coefficients table
What law says that heavier objects requier more force then lighter objects?
More force for what?According to Newton's Second Law, F=ma (force = mass x acceleration), it requires more force to accelerate a more massive object.On the other hand, do some reading, in basic physics books, about friction - even to maintain a constant speed, the force required to overcome friction is also proportional to an object's weight. The force of friction is equal to the "normal" force - the force perpendicular to the surface of contact, multiplied by a coefficient of friction. The coefficient of friction is typically somewhere between 0.2 and 1.0, depending on the types of surfaces.
What is the amount of horizontal force required to start in motion an object sitting on a horizontal surface must be great than what?
multiply coefficient of static friction by object mass
A 40kg crate is at rest on a level surface if the coefficient of static friction between the crate and the surface is 0.69 what horizontal force is required to get the crate moving?
276 Newtons. Coefficient of static friction is a ratio between the force it takes to budge the object over the normal force (mass times gravity). So: 0.69 = Force / 400 N (40 kg times 10 m/s^2, the force of gravity). Solve for 276 N.
If you know the coefficient of friction how do you find the maximum velocity to maintain a circular path at a given radius?
say mass(m) = 10 kg, radius(r) = 10 m, say friction coefficient = 0.5 force to break friction = 10 * 0.5 = 5 kgf = say 50 n to find acceleration required to produce this force use f=m*a, shuffle to a = f / m so a = 50 / 10 = 5 (m/s)/s, install in a = v^2 / r, so 5 = v^2 / 10, so 10 * 5 = v^2, so sq. root 50 = v, so v = 7.07 metres / second if friction coefficient and radius remain the same, altering the mass wont alter the velocity at breakaway point
What is required to get a stationary object moving?
An outside force is needed. If friction comes into play (which it likely will), the magnitude of the applied force must be greater than the force of friction acting upon the object in order for the object to move. FYI, the force of friction is equal to the coefficient of static friction times the normal force (equal to the weight of the object).
What horizontal force P is required to drag a sack of rice weighing 110 pounds. in a horizontal floor if the coefficient of friction between the floor on the sack of rice is 0.25?
27.5 lbs
How do you find the coefficient of static friction?
Use the formula: FsMAX=μsFN if you want to do it experimentally, get the two different surfaces, and angle one until the object on top starts moving. take the tangent of the angle that starts the objects sliding past one another, and that is your coefficient of static friction.
