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ab+bc+ca
It could be a vector sum.
AB + BC = AC The sum of the parts equals a whole :]
A rational number is one that can be expressed as a/b The sum of two rational numbers is: a/b + c/d =ad/bd + bc/bd =(ad+bc)/bd =e/f which is rational The difference of two rational numbers is: a/b - c/d =ab/bd - bc/bd =(ab-bc)/bd =e/f which is rational The product of two rational numbers is: (a/b)(c/d) =ac/bd =e/f which is rational
yes it will definitely help you for BC next year.
Assuming ABCD marks the four corners, the perimeter = sum of the four sides = (AB + BC + CD + DA) where AB == the side from A to B etc.
yes because ab plus bc is ac
There are some missing terms. First of all, I assume that A, B, and C are collinear and that B is between A and C.If this is true then AC-AB=BC by the whole is the sum of its parts theorem.24-20=4Otherwise, all that can be said about BC is that it's length is between AC-AB = 4 and AC+AB = 44 units.
Commutativity.
mdpt: point line or plane that bisects a line so that AB=BC. mdpt theorem: point or plane that bisects a line so that AB is congruent to BC.
ab 4
All the trigonometric functions are derived from the right angled triangle. If we consider the three sides (AB, BC, CA) of a triangle and the included angle. There is a possibility of getting six functions based on the ratios like AB/AC, BC/AC, AB/BC, BC/AB, AC/BC, AC/AB . So we will have six trigonometric functions