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The half-life of radon-222 is about four days. After how many days is the amount of radon-222 equal to one-sixteenth of its original amount?
Wiki User
∙ 12y ago
Let's step through the half-life of radon to see how it works. Radon-222 starts at full strength. In four days (its half-life), it is at half strength. In four more days, it is again at half strength (of the half strength) for a total of 1/4 strength. In four more days, it is again half the strength (of the 1/4 strength) for a total of 1/8 strength. In four more days, it is another half life weaker, for a total of 1/16 strength. In 16 days, this isotope of radon has just 1/16th the original radiation.
Wiki User
∙ 12y ago
Wiki User
∙ 14y ago15.2 days is 3.979 half lives (15.2/3.82)
Therefore there will be .53.979 = .0634 of the initial sample or .277 micrograms.
Use the half life equation of N=No(1/2)(t/T) for a direct calculation, where N is the remaining amount, No is the original amount, t is the amount of elapsed time and T is the length of one half life.
Wiki User
∙ 13y agoHere, t1/2 = 4 days
So, k = 0.693/4 days-1 = 0.17325 days-1
Time for decay of 1/4 of the sample,
t1/4 = 0.693/k = 0.693/0.17325 = 4 days
After 4 days the amount remaining will be 1/4 of the original amount.
Wiki User
∙ 9y agoAccording to this data, in the first four days, the amount of radon will go down to one-half the original amount. That is, you can divide the initial amount by 2. AFter another four days, the remaining radon will again be divided by 2.
Wiki User
∙ 6y agoThe half-life of Radon 222 is 3.8 days. That means every 3.8 days, the amount left is cut by one half.At the end of 3.8 days, it is half. Add another 3.8 days (7.6 days total) it is 1/4. at 11.4 days, 1/8th. Add another 3.8 days, and at 15.2 days it is 1/16th of the original amount.
Wiki User
∙ 10y agoApproximately 1 gram.
The 5 reductions represent a reduction to 1/25 or 1/32 the original mass.
32/32 = 1 gram
Wiki User
∙ 14y agoAfter 7,647 days.
Wiki User
∙ 14y ago11,46 days
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