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Q: If the individual voltage of each load in a parallel circuit are equal to?

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The current in each individual component of the parallel circuit is equal to (voltage across the combined group of parallel components) / (individual component's resistance). The total current is the sum of the individual currents. ============================== Another approach is to first calculate the combined effective resistance of the group of parallel components. -- take the reciprocal of each individual resistance -- add all the reciprocals -- the combined effective resistance is the reciprocal of the sum. Then, the total current through the parallel circuit is (voltage across the parallel circuit) / (combined effective resistance of the components).

in a parallel circuit resistance decreases increasing the current.

The voltage drop in any branch (closed loop) of a series parallel circuit is equal to the APPLIED VOLTAGE(NOVANET) Without looking in my codebook, I believe it is 2% on a branch circuit.

In all branches of a parallel circuit, it is voltage that is the same. Across each parallel branch of a circuit, we'll measure the same voltage. Probably the best example of equal voltages appearing across all branches of a parallel circuit is a household electrical distribution curcuit. The voltage at any outlet where you'd care to plug in an appliance or device will be the same. A fan plugged into an outlet in a bedroom will "feel" the same voltage as it would if it were in the living room and plugged into an outlet there.One other way to look at things like this is that each branch of the parallel circuit is connected across the voltage source. Each branch could be looked at as an "independent" circuit, and any given branch doesn't care what is happening in any other branch. Does turning that fan we mentioned on and off, or even unplugging it from the outlet affect the operation of, say, the refrigerator? No, it does not. Any device plugged into an outlet is connected "directly" to the source of voltage. And each parallel branch of the circuit will operate independently of any other branch. We know that the voltage in (or across) any branch of a parallel circuit is the same as the voltage across any other branch.

By Kirchhoff's Voltage Law, the sum of the voltage drops around the series circuit will equal the voltage applied to the circuit.

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The current in each individual component of the parallel circuit is equal to (voltage across the combined group of parallel components) / (individual component's resistance). The total current is the sum of the individual currents. ============================== Another approach is to first calculate the combined effective resistance of the group of parallel components. -- take the reciprocal of each individual resistance -- add all the reciprocals -- the combined effective resistance is the reciprocal of the sum. Then, the total current through the parallel circuit is (voltage across the parallel circuit) / (combined effective resistance of the components).

The voltages appearing across each branch of a parallel circuit will be equal to the supply voltage.

Components in a parallel circuit share the same voltage. Etotal = E1 = E2 = . . . EnTotal resistance in a parallel circuit is less than any of the individual resistances. Rtotal = 1 / (1/R1 + 1/R2 + . . . 1/Rn)Total current in a parallel circuit is equal to the sum of the individual branch currents. Itotal = I1 + I2+ . . . In Answered by MD.Nazeer Ahmed,MCET Student.

Yes, if it is a series circuit. In an ideal parallel circuit, there is equal voltage in each leg. In a real circuit, results may vary if there is voltage loss in the wiring.

For each individual branch, you can use Ohm's Law - just divide the voltage by the resistance.

The current through each resistor is equal to the voltage across it divided by its resistance for series and parallel circuits.

Kirchoff's voltage law: In a series circuit, the signed sum of the voltage drops around the circuit add up to zero. Since a parallel circuit (just the two components of the parallel circuit) also represents a series circuit, this means that the voltage across two elements in parallel must be the same.Kirchoff's current law: The signed sum of the currents entering a node is zero. In a series circuit, this means that the current at every point in that circuit is equal. In a parallel circuit, the currents entering that portion of the circuit divide, but the sum of those divided currents is equal to the current supplying them.

zero? the supply voltage? the supply voltage minus the individual coltage drops? the sum of the individual voltage drops? which one?

-- The voltage across every circuit element is the same, and is equal to the power supply voltage. -- The current through each circuit element is in inverse proportion to its impedance. -- The sum of the currents through all circuit elements is equal to the power supply current.

in a parallel circuit resistance decreases increasing the current.

The voltage across a battery in a parallel circuit is equal to the voltage across each bulb because Kirchoff's Voltage Law (KVL) states that the signed sum of the voltages going around a series circuit adds up to zero. Each section of the parallel circuit, i.e. the battery and one bulb, constitutes a series circuit. By KVL, the voltage across the battery must be equal and opposite to the voltage across the bulb. Another way of thinking about this is to consider that the conductors joining the battery and bulbs effectively have zero ohms resistance. By Ohm's law, this means the voltage across the conductor is zero, which means the voltage across the bulb must be equal to the voltage across the battery and, of course, the same applies for all of the bulbs.

Yes