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You mean the image of the object after it focuses though mirror of a lens? To know that, you would also have to know the distance from the object to the lens/mirror and either distance to the image or focal length of the lens/mirror or magnification. So in other words, there is not enough information in the question.
This question should be pretty straight forward, so I recommend to just read your physics book/notes.
What else can I help you with?
An object is located 51 millimeters from a diverging lens the object has a height of 13 millimeters and the image height is 3.5 millimeters how far of the lens is?
13.7 millimeters
An object 51 millimeters from diverging lensthe object has a height of 13 millimeters and the image height is 3.5 millimetershow far in frontof the lens is the image located?
13.73076923 mm.
An object is located 51 millimeters from a diverging lens the object has a height of 13 millimeters and the image is 3.5 meters how far in front of the lens is the image located?
13.7 millimetersThis answer is correct, but the formula is most important.The formula is:Hi = height of imageHo = height of objectSi = Distance of image from lensSo = Distance of object from lensYou are trying to find Si, so that is your unknown.Here is your formula: Hi/Ho = Si/SoOr in this case: 3.5/13 = Si/51The rest is basic algebra.Good luck!You can use the ratio equation; (Image Height)/(object height) = - (image location)/(object location) In your case you will get a negative location which means the image is on the same side of the lens as the incoming light.
An object is 51 millimeters from a diverging lens the object has a height of 13 millimeters and then image height is 3.5 millimeters How far in front of the lens is the image located?
The image distance can be calculated using the lens formula: 1/f = 1/d_o + 1/d_i, where f is the focal length of the lens, d_o is the object distance, and d_i is the image distance. Given that the object distance (d_o) = 51 mm and object height = 13 mm, image height = -3.5 (negative since it is inverted), we can use the magnification formula to find the image distance (d_i). The equation for magnification is M = -d_i/d_o = -hi/ho, where hi is the image height and ho is the object height. Solving these equations will give the image distance in front of the lens.
When an object is placed 8 millimeters from a concave spherical mirror a clear image can be projected on a screen 16 millimeters in front of the mirror. If the object has a height of 4 millimeters the?
c. 8 millimeters
An object located 51 millimeters from a diverging lens the object is 13 millimeters high and the image 3.5 millimeters how far in front of the lens is the image located?
Since the image is virtual and upright, it is located on the same side as the object. Using the lens formula 1/f = 1/dO + 1/dI, where f is the focal length, dO is the object distance, and dI is the image distance, you can calculate the image distance. Given the object distance (51 mm), object height (13 mm), and image height (3.5 mm), it would be possible to determine the image distance and thus find out the distance from the lens at which the image is located.
An object is located 51 millimeters from a diverging lens the object has a height of 13 millimeters and the image height is 3.5 millimeters how far in front of the lens is image located?
Since the image height is smaller than the object height, it is a virtual image. Using the thin lens equation (1/f = 1/d_o + 1/d_i), where d_o is the object distance and d_i is the image distance, and assuming a diverging lens, the image distance is found to be -17.17 mm. This means the image is located 17.17 mm in front of the lens.
An object is located 51 millimeters from a diverging lens the object has a height og 13 millimeters and the image height is 3.5 millimeters how far in front of the lens is image located?
hi/ho = di/do di = dohi/ho di = (51mm)(3.5mm)/(13mm) di = 14mm * rounded to 2 significant figures The image would be 14mm in front of the lens.
When an object is placed 8 millimeters from a concave spherical mirror a clear image can be projected on a screen 16 millimeters in front of the mirrorif the object has a height of 4 millimeters the?
The Correct Answer would be 8 millimeters.8 millimeters
An object is located 51 millimeter from a diverging lens the object has a height of 13 millimeter and the image heightg is 3.5 millimeters how far in front of the lens is the image located?
7
An object is 5 millimeters high is located 15 millimeters in front of a plane mirror how far from the mirror is the image located?
The image will be located the same distance behind the mirror as the object is in front of it, so the image will be 15 millimeters behind the mirror.
How do i find magnification of the image?
To find the magnification of an image, use the formula ( \text{Magnification} (M) = \frac{\text{Image Height}}{\text{Object Height}} ) or ( M = \frac{\text{Image Distance}}{\text{Object Distance}} ). If you have the dimensions of the object and the image, divide the height of the image by the height of the object. Alternatively, if you have the distances from the lens to the image and the object, use the second formula for magnification.
