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Q: If the race covers 120 miles over 6 days and the cyclists ride the same distance each day how many miles dose each cyclist ride each day?
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If A cyclist bikes x distance at ten miles per hour and returns over the same path at eight miles per hour What is the cyclists average rate for the round trip in miles per hour?

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When two cyclists begin traveling in the same direction on the same bike path One travels at 15 miles per hour and the other travels at 12 miles per hour when will the cyclists be 10 miles apart?

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If a cyclist takes 4 hours to travel 72 miles what is the cyclists average speed in miles per hour?

Velocity = distance / time Given d = 72 miles ; t = 4 hour V = 72 miles / 4 hour = 18 miles per hour


Two cyclists start biking from a trail's start 3 hours apart The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour How much?

Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking? A. 2 hoursB. 4 ½ hoursC. 5 ¾ hoursD. 6 hoursE. 7 ½ hours AnswerThe distance the 1st cyclist travels is 6(3+t) miles, andthe distance the 2nd cyclist travles is 10t miles...where t=the number of hours since cyclist #2 starts.Now solve: 6(3+t)=10t ==> 18+6t=10t ==> 18=4t ==> t=4.5 hrs==> 4.5 hours = 4 hrs 30 minutes


Two cyclists begin traveling in the same direction on the same bike path one travels at 15 miles per hour and the other travels at 12 miles per hour when will the cyclists be 10 miles apart?

Answer:3 1/3 hours or 3 hours and 20 minutesSolution:distance = velocity x timethe distance travelled by the first cyclist = 15 x timethe distance travelled by the second cyclist = 12 x timethe difference distance = 15 x time - 12 x timethis difference will be 10 miles when15 x time - 12 x time = 103 x time = 10time = 10/3 = 3 1/3 hours= 3 hours and 20 minutes.


If A cyclist bikes x distance at 10 miles per hour and returns over the same path at 8 miles per hour. What is the cyclist's average rate for the round trip in miles per hour?

The average speed for the entire trip is 9mph.


A cyclist bikes x distance at 10 miles per hour and returns over the same path at 8 miles per hour what is the cyclist's average rate for the round trip in miles per hour?

The average speed is 8 and 8/9 mph.


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Two cyclists start biking on a trail. Cyclist 2 travels at 10 mph and starts 3 hours after cyclist 1 who is traveling at 6 mph. How much time does it take for cyclist 2 to catch cyclist 1?

ANSWER # 1 It looks like cyclist #2 is out to catch cyclist #1. Our #2 cyclist is starting out 3 hours later than cyclist #1, and is traveling at 10 mph versus the 6 mph of cyclist #1. There are a couple of ways to solve this one, so there is no "right way" to do it. Opting for an easy one, let's think of it this way. Think of it like both cyclists are going the same speed, the 6 mph. Yes, our trailing cyclist can't ever catch the lead cyclist, but this is a short cut, okay? If both cyclists ride, the space between them neither increases or decreases. Here's the scoop. It's the space between them that we're gonna look at. That space is 3 hours long. Here's the thinking. Cyclist #2 is going faster than #1 by 4 mph, and that is the "extra" speed that our #2 cyclist is using to close the gap, to make up that 3 hours. If cyclist #2 is going to make up 3 hours at 4 mph (the differential speed), how much ground is he going to have to make up? Well, cyclist #1 is riding at 6 mph for 3 hours to create the gap. That's 6 time 3 or 18 miles that cyclist #2 is going to have to make up. And our #2 guy is going to have to make up the 18 miles at 4 mph (the differential speed). How long is it going to take him? The 18 miles divided by 4 mph equals 4 ½ hours. Presto. It will take our #2 cyclist that 4 ½ hours to catch up to cyclist #1. If we want to check our work, take cyclist #2's 10 mph speed and multiply by 4 ½ hours and we'll see that he has to ride 45 miles to catch cyclist #1. Let's see what happens for cyclist #1. This cyclist will be riding for 4 ½ hours plus the 3 hour head start. That's 7 ½ hours of riding at 6 mph. The 7 ½ times 6 equals 45 miles. Check! We're good here! ANSWER # 2 1st = 6(x +3) ......... 2nd = 10x 10x = 6(x+3) x = 4 (1/2)


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