If you have a simple circuit. For eg: One voltage source and one resistor, then the voltage of the circuit will always remain the same, the current however will decrease following Ohms' Law V=I*R.
If we have a current source instead of a voltage source, we are forcing the current to be a certain value so if we increase the resistor value the current will remain the same but the voltage will increase.
If voltage increases when current remains constant then resistance must also increase. Ohm's Law: Voltage = Current times Resistance.
Ohms Law says Voltage = Current x Resistance. Hence if voltage rises, so will current.
You have it backwards, the resistance controls the current not the current controls the resistance. I = E/R . Your question should read, "If the voltage is constant and the resistance in the circuit is increased what happens to the current?" Say the voltage is 120 volts and the resistance is 30 ohms, I = 120/30 = 4 amps. Now we double the resistance to 60 ohms, then I = 120/60 = 2 amps. So now you can see if you increase the resistance the current drops.
A: That will happen anytime the voltage source is not able to provide the power needed for the load. If the load exceed the power available from the source the voltage will be reduced as IR drop from the source
A: Nothing will happen if the load increases or even removed the voltage will go to the open voltage condition no harm.
If the resistance increases, while the voltage stays the same, current will decrease. Current = voltage divided by resistance
If voltage increases when current remains constant then resistance must also increase. Ohm's Law: Voltage = Current times Resistance.
The current will also increase. This can be proved by using ohms law, V=IR --> I=V/R, as the resistance is constant the R can be replaced by the number 1 therefore I=V/1 or I=V, hence if the voltage increases the current must also increase.
According to ohms law, V = IR, where V=voltage I= current R = resistance the above formula can also be written as I = V/R, here, resistance is inversely proportional to current. In other words, as resistance increases, current decreases.
If resistance is increased, current decreases. Ohm's Law: current equals voltage divided by resistance.
Nothing, but the current will increase.
by the ohms law we can clearly say that the current is the ratio of voltage to the resistance.as the resistance is doubled the current should be halved.
According to ohms law (V=IR)if voltage is increased the current also increases keeping the resistance same .In other words, to keep values on the both sides of equal sign current must increase with the voltage when the resistance is constant. For example: if R=1 and V=2 then I=2 and if voltage is increased to 4 then current also increases with voltage to 4.CONCLUSION:V IS DIRECTLY PROPORTIONAL TO I KEEPING THE R CONSTANT
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Ohms Law says Voltage = Current x Resistance. Hence if voltage rises, so will current.
You have it backwards, the resistance controls the current not the current controls the resistance. I = E/R . Your question should read, "If the voltage is constant and the resistance in the circuit is increased what happens to the current?" Say the voltage is 120 volts and the resistance is 30 ohms, I = 120/30 = 4 amps. Now we double the resistance to 60 ohms, then I = 120/60 = 2 amps. So now you can see if you increase the resistance the current drops.
A: That will happen anytime the voltage source is not able to provide the power needed for the load. If the load exceed the power available from the source the voltage will be reduced as IR drop from the source