The mass is 15,9 kg for 3,785 US gal.
Approx 1122 poundals.
If you think to sodium hypochlorite the density is 1,11 g/cm3.
answer lies within "specific gravity".
1,100 litres is equivalent to 290.589 US gallons (rounded), regardless of what's in the liters. Even if they're completely empty.
There is no such thing as a specific gravity for any element.
Head pressure=specific gravity*1000*gravity*height. Therefore if specific gravity is increased head pressure will increase.
If you think to sodium hypochlorite the density is 1,11 g/cm3.
(Tonnes / specific gravity) * 264.17 = gallons (US) (Tonnes / specific gravity ) * 219.97 = gallons (impereal) Example: 1 Tonne fuel oil , specific gravity 0.89 , US gallons ? (1 / 0.89) * 264.17 = 296.82 US gallons (approx)
These are incompatible units
It depends on what material makes the gallons and it's specific gravity.
It depends on the concentration.
1.3
489 grams
It depends on the solution's degree of concentration or dilution.
Electrolyte of sulphuric acid to a specific gravity of 1250.
start with known values Specific gravity = 1.0 for water weight = 100 pounds 100pounds/8.36 pounds per gallon = 11.96 gallons ------------------------------------ Specific gravity = 1.5 for unknown liquid weight = 100 pounds 100pounds/ (8.36 pounds per gallon of water * 1.5) = 7.97 gallons At least that's how I wuold do it....
First, you must know the specific gravity of the liquid then you can calculate the weight by multiplying the specific gravity by 8.34 lbs. 8.34 lbs is the weight of a gallon of water that has a specific gravity of 1.
For this I will use water as the unit of measure. Based on the lbs per gallon of water @ 4 degrees Celsius which is 8.33 8.33 is a specific gravity of 1 The equation to determine lbs per gallon using a basis of water lbs per gal = (sg * 8.33) So if you have 0.8349 as your specific gravity: (0.8349 * 8.33) = 6.954717 (lbs per gal) The equation to convert pounds to gallons of a different fluid that has a variable specific gravity would be: gallons = lbs / (sg * 8.33) If I have 5 pounds of a lubricant with a SG of 1.2 5 / (1.2 * 8.33) = 0.5 (gallons) http://www.engineeringtoolbox.com/water-gallons-pounds-d_1710.html