the current will increase because of a lower level of resistance , hence more current will flow- easily
If current decreases, and resistance is a constant, then voltage must also decrease.
When energy input remains constant and voltage remains the same in a circuit but current decreases, power decreases proportionally to current.
Based on the simplest Electrical Equation V = I * R,(reads: voltage equals current multiplied by resistance)then, rearranged I = V / R .As resistance decreases, current flow proportionately increases
V = IR Where, V = voltage I = current R = resistance Thus if resistance is increased with constant voltage current will decrease
If the ratio of voltage to current is constant, then the circuit is obeying Ohm's Law. If the ratio changes for variations in voltage, then the circuit does not obey Ohm's Law.
Yes, if the resistance remains constant. Power is voltage times current, and current is voltage divided by resistance, so power is voltage squared divided by resistance. In essence, the power increases as the square of the voltage.
No. Current and voltage are directly proportional to one-another and both are related to resistance by Ohm's law: V = IR or Volts = Current * Resistance So the current will depend upon the voltage and the circuit resistance by rearranging the above equations: I = V/R Meaning that the current will decrease as circuit resistance is increased if the voltage remains constant.
Current will increase
Current increases if the voltage remains constant.
The resistance is decreasing
In a passive circuit, the current will decrease. In an active industrial circuit, it will usually decrease. In a theoretic manner - it is an unknown.
If the voltage applied across the resistor remains constant, then as the resistance of the resistor decreases, the current through it will increase. Consider Ohm's Law: E = IR In this formula, in order for 'E' to remain constant as 'R' decreases, 'I' must increase. Another form of Ohm's Law: I = E/R If 'E' remains constant, then the value of the fraction increases as its denominator 'R' decreases.
The physical equation governing voltage is V = IR, where V is voltage, I is current, and R is resistance. If V remains constant while R is increased, I or current must decrease. Increasing the resistance in a circuit is simply introducing a material that further resists or impedes the electron flow (current), thus current decreases.
Ohm's Law: voltage = current * resistance. If resistance is a constant, then voltage is directly proportional to current.
Power is voltage times current. If power and voltage remains the same, then current cannot decrease - it must also remain the same.The only viable explanation, assuming the question is valid, is that there is a parallel circuit, and one resistance increases while the other decreases, keeping the net resistance the same, but shifting the power from one branch to the other.Another answerNormally, if the voltage remains the same and the current decreases in a particular circuit, then the resistance of that circuit must be increasing and the total energy input must also reduce.If the total energy input remains constant (and yet the voltage remains the same) then some of the current being supplied by the source - and therefore also some of the energy - must be going to some other place outside the circuit in question, e.g. there could now be a ground fault...
Based on the simplest Electrical Equation V = I * R,(reads: voltage equals current multiplied by resistance)then, rearranged I = V / R .As resistance decreases, current flow proportionately increases
If resistance is halved while voltage remains constant, the current will double.
It is halved. coz voltage=current * resistance
If the current through a pure metallic conductor causes the temperature of that conductor to rise, then its resistance will increase. A practical example of this is an electric lamp. The cold resistance of a lamp is very much lower than the hot resistance.