Lets take the basic case of if you have a 2V battery with a resistor going from the positive terminal to the negative one. V = i*R and P = V*i are the two equations that you need to know; solve the first one for i, so i= V/R and sub it into the second equation, so P = V*V/R, or P = V^2/R. Now you can see in this setup, if you double the voltage, the power is multiplied by 4.
Increase the voltage across the resistor by 41.4% .
no voltage will be induced on the secondary side of the motor as the windings will become saturated.
You would connect them in series to double the output voltage.
basically a diode flows an exponential curve Vs current if you try to double the voltage drop by increasing the voltage it should self destruct
In that case, the current will also be doubled. This follows from Ohm's Law (current = voltage / resitance)
Voltage is equal to the Current multiplied by the Resistance.Without changing the resistance, increasing the applied voltage in a circuit will increase current flow. There is a simple, direct relationship between voltage and current. Double the voltage, twice the current will flow. Triple the voltage, and the current will triple. As voltage (E) equals current (I) times resistance (R), when resistance is fixed, what happens to voltage will happen to current.
This is Ohm's law. It says that voltage (E) equals current (I) times resistance (R). It can be written three ways, and here they are: E = I x R I = E / R R = E / I Voltage and current are directly proportional. What happens to one will happen to the other. What this says is that for a fixed resistance, increasing the voltage will cause an increase in current. Or, said another way, to increase the current through a given resistance, the voltage must be increased. Further, if you double the voltage applied to a given resistance, the current will double. Simple and easy.
UJT means Uni Junction transistor terminals are Emitter,Base1 and Base2.UJT is also called double base diode.UJT operates when the emitter is forward biased.voltage is applied between base1 and base2.If an external voltage is applied at terminal E,no current will flow in to the emitter as long as this applied voltage is less than emitter voltage.When this applied voltage exceeds emitter voltage,current will flow into the emitter and holes get injected from emitter to base1 and are repelled by base2.This results in increase in the region between the junction and the base 1.The increase in conductivity results drop in emitter voltage and increased forward bias of the junction.so emitter current also increases.Then it exhibits a negative resistance.
Increase the voltage across the resistor by 41.4% .
Increase primary voltage but decraease amerage - eg double voltage and half amperage. This will double your secondary voltage. "Transformed" voltage is easy to understand by following this simple math rule. secondary voltage divided by primary voltage = no of turns on secondary and no of turns on primary. eg; 240v \ 12v = 20 (factor) this means the secondary winding is 20x the primary winding. Basically thats all I know Stick to this rule for step up & step down tranforming & you'll be sweet.
If the load resistance is constant, then increasing the voltage will increase the current by the same proportion -i.e. doubling the voltage will double the current.
no voltage will be induced on the secondary side of the motor as the windings will become saturated.
The heat released by the rheostat with double the voltage will quadruple. When voltage is tripled, the power loss is 32 or 9 times that before. A rheostat is a kind of variable resistor. Since E = IR (voltage equals current times resistance), then I = E/R (current equals voltage divided by resistance). If the voltage is doubled and the resistance stays the same, then--you can see by the formula--the current would double. Now, power dissipated by a resistor is related to the product of the current and voltage (P = IE). But since a doubling of voltage produces also a doubling of current, double the current results in 2X2=4 times the power (heat) loss.
Ohm's law states it is. Double the voltage with the same resistance will double the current. E = IxR. 120 = 10 x 12. 240 = 20 x 12.
The current will increase and will flow more. If voltage increases, current must increase.
In common, any application if voltage is increased current will be the small amount. at the same if voltage Decreased current will be increased...AnswerAccording to Ohm's Law, 'the current flowing through a conductor is directly proportional to the applied voltage, provided certain conditions, such as temperature, remain constant'. So if you double the voltage, the resulting current will double; if you halve the voltage, the current will halve.
The coil will burn out due to having almost double the voltage being applied to it.