7 peices of fruit
2 bananas. you also have 3 apples
Solve the problem by treating it as a simultaneous equation question which works out as: Apples: 0.20 each Oranges: 0.10 each
Oranges cost 6 cents each. Apples cost 10 cents each.
If there were three bananas, and you've taken one banana, then there are two bananas left.
In general, try to remember to keep your ratios in a form of 'this' to 'that' and 'this' to 'that'. For example, 3 apples : 6 oranges; 2 apples: 4 oranges. All ratios remain true regardless of which is on "top" (the numerator). It's only important to remain consistent and choose ratios that will be effective for the given problem.
you have 7 oranges and 7 applesBig hands.
2 bananas. you also have 3 apples
Treat it as a simultaneous equation and it works out as: Oranges = 0.10 each Apples = 0.20 each
Solve the problem by treating it as a simultaneous equation question which works out as: Apples: 0.20 each Oranges: 0.10 each
Oranges cost 6 cents each. Apples cost 10 cents each.
Total = 6 fruits. 2 Apples = all but 4. 2 Bananas = all but 4. 2 Oranges = all but 4.
8:3
Think of adding like things, for example, adding apples to apples and oranges to oranges. If you have 1/2 and 1/4 they are not "like" things. However, if we have 2/4 and 1/4, they are both 4ths. Since they are both 4ths they are "like things," and we can add 2 of them to 1 of them andhave 3 of them. So we add 2/4 and 1/4 and have 3/4
If there were three bananas, and you've taken one banana, then there are two bananas left.
There are about 4 small apples, 3 medium apples, or 2 large apples in a pound.
Mathematically, you would have 1. 4 - 3 = 1 On the other hand, depending on how you think. If you take 3 from 4, then you would have 3 apples.
In general, try to remember to keep your ratios in a form of 'this' to 'that' and 'this' to 'that'. For example, 3 apples : 6 oranges; 2 apples: 4 oranges. All ratios remain true regardless of which is on "top" (the numerator). It's only important to remain consistent and choose ratios that will be effective for the given problem.