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17.....you said it in the question.
This volume is 6,197 399 5 at 25 0C.
The properties of an ideal gas are summed up in chemistry and physics in this neat equation: PV = kT This is saying that (pressure) multipled by (Volume) = (the constant 'k') times (Temperature) . Without getting into all the units and the details, in order to answer this question we only have to understand that when one side of the equation increases, the other side of the equation has to increase by the same multiplier. Increasing the pressure from 25 ATM to 100 ATM, the left side of the equation (PV) is multiplied by 4. (The volume of the tank 'V' remains constant.) If propane behaves like an ideal gas or close to it, then the right side must also multiply by 4, and the absolute temperature becomes 4 times as great. If the tank is perfectly insulated and none of the heat escapes, then the gas in it rises in temperature from 275 K to 1100 K.
Solid
25 ml. The volume would not change. Now pressure on the other hand...
nothing
Assuming pressure stays constant, the volume decreases by 25%. PV = nRT.
The universal gas equation is PV = nRT (Pressure x Volume = Number of moles x Universal Gas Constant x Temperature in Kelvin/Rankin). So - if Pressure is constant, the number of moles is constant, but the temperature increases from 25C (298 K) to 125C (398K) - a 34% increase, a similar 34% increase in volume will occur.
285 K?
17.....you said it in the question.
A fixed quantity of gas at a constant pressure exhibits a temperature of 27 degrees Celsius and occupies a volume of 10.0 L. Use Charles's law to calculate: the temperature of the gas in degrees Celsius in atmospheres if the volume is increased to 16.0 L
58 F
Yes, fluorine is a gas at room temperature/25 degrees Celsius.
Assuming the gas follows the ideal gas law (which at these temperatures and pressures should be a good assumption), T2/T1 = P2V2/P1V1 so T2 (final temperature) = T1 x P2V2/P1V1 Temperature has to given in absolute temperature for this to work, so we first convert T1 25°C = 278.15 K. T2 = (278.15 K)(47.3 kPa)(7.0 L)/(95.3 kPa)/(2 L) = ~386.55 K = ~113.40 °C If it seems strange to you that the temperature went UP when the gas expanded, consider this... If the temperature remained constant, then as the pressure dropped to 47.3 kPa, the volume would only increase to about 5 L. To make the volume increase to 7 L at that pressure you would have to heat the gas up get it to expand.
50.0 grams of what gas? This is the ideal gas law. Pressure * Volume = moles gas * the R constant * temperature in Kelvin PV = nRT
It would be approx 9042 litres.
This volume is 6,197 399 5 at 25 0C.