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Assuming the gas follows the ideal gas law (which at these temperatures and pressures should be a good assumption),

T2/T1 = P2V2/P1V1

so

T2 (final temperature) = T1 x P2V2/P1V1

Temperature has to given in absolute temperature for this to work, so we first convert T1 25°C = 278.15 K.

T2 = (278.15 K)(47.3 kPa)(7.0 L)/(95.3 kPa)/(2 L) = ~386.55 K = ~113.40 °C

If it seems strange to you that the temperature went UP when the gas expanded, consider this...

If the temperature remained constant, then as the pressure dropped to 47.3 kPa, the volume would only increase to about 5 L. To make the volume increase to 7 L at that pressure you would have to heat the gas up get it to expand.

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