2.
Hey Baby!!
The mass of nitrous oxide is 262,8 g.
5.36 g
CaCO3 + 2HCl -> CaCl2 + CO2 +H2O
4
Following the Law of Conservation of Mass (see link below), there will be 20 grams of products in a reaction of 20 grams of reactions.
hi
2Fe + 3S >> Fe2S3 48.0 grams S (1 mole S/32.07 g)(2 Fe/3 mole S)(55.85 g/1 mole Fe) = 55 .7 grams of iron needed
1000 grams = 1 kilogram So dividing grams by 1000 yields kilograms
The mass of nitrous oxide is 262,8 g.
14.10 ounces
2
C3H8 + 5O2 --> 3CO2 + 4H2O 2.75 mole C3H8 (5 moles O2/1 mole C3H8)(32 grams/1 moleO2) = 440 grams oxygen required =====================
First you have to balance the equation N2 + H2 ---> NH3 N2 +3H2 ---> 2NH3 Then you have to use the Molecular Weight and number of mols required for complete reaction of each one to go from 14g N2 + xg of H2 to get the final result.
cuo
20 grams = 20,000 milligrams 20,000/100 = 200. So, 20 grams yields 200 doses of 100 mg.
431.5 grams A+LS =^.^=
The equation for the reaction is 4 Na + O2 -> 2 Na2O. This shows that, for complete reaction, one mole of oxygen is required for each four gram atomic masses of sodium. The gram atomic mass of sodium is 22.9898; therefore, 46 grams of sodium constitutes 2.00 moles of sodium, to more than the justified number of significant digits. The gram molecular mass of diatomic oxygen is 31.9988; therefore 160 grams of oxygen constitutes 5.000 moles of diatomic oxygen, to more than the justified number of significant digits. This is well over the minimum amount of oxygen required for complete reaction of all the sodium present. Each two gram atomic masses of sodium produces one gram formula mass of sodium oxide; therefore, the number of gram formula masses of sodium oxide produced is 1.00, to at least the justified number of significant digits.