0
How much iron is required to react with 48.0 grams of sulfur in the reaction 2Fe plus 3S yields Fe2S3?
Wiki User
∙ 13y ago
2Fe + 3S >> Fe2S3
48.0 grams S (1 mole S/32.07 g)(2 Fe/3 mole S)(55.85 g/1 mole Fe)
= 55 .7 grams of iron needed
Wiki User
∙ 13y ago
Add your answer:
Earn +20 pts
In the reaction 2 Fe plus 3 S--- Fe2S3 how much iron is required to react with 48.0 g of sulfur?
55,73 g of iron
What is the chemical formula for ferrous disulfide?
ferric indicates the iron is +3 as opposed to +2 for ferrous sulfide indicates that there is sulfur with a -2 charge the formula is Fe2S3 two iron ions with a +3 = +6 3 sulfur ions with a -2 = -6 -6+6 = 0
Formula for iron iii sulfide?
These are the ions and their charges: Fe+3 SO3-2The charges have to add up to zero, so two +3 iron ions cancel out three -2 sulfite:Fe+3 Fe+3 SO3-2 SO3-2 SO3-2Simplify: Fe2(SO3)3
How does iron form?
If you're talking about Iron (II) Sulfide, where the oxidation of Iron is 2+, 2 electrons from the Iron atom is transferred to the Sulfur atom, producing Fe2+ and S2- .
What is the chemical formula for iron sulfate?
The chemical formula is... Fe2S3
In the reaction 2 Fe plus 3 S--- Fe2S3 how much iron is required to react with 48.0 g of sulfur?
55,73 g of iron
Metallic Iron was heated with solid sulfur to form a single solid sulphate what is the balanced chemical reaction?
2Fe + 3s = Fe2S3
Why the mixture of the metal fillings and sulfur becomes chemical change when heat was applied?
Applying heat to the mixture causes a chemical reaction to occur: 2Fe + 3S -> Fe2S3
What type of reaction is Fe2S3 equals 2Fe plus 3S?
decomposition
How many milliliters of 0.200 M FeCl3 are needed to react with an excess of Na2S to produce 2.75 g of Fe2S3 if the percent yield for the reaction is 65.0 percent?
.2M x V FeCl3=moles FeCl3 x 1mole Fe2S3/2mole FeCl3=moles of Fe2S3 x mm of Fe2S3/1 mole Fe2S3= g Fe2S3 x .65% yield. 2.75g Fe2S3/ .65= 4.23g Fe2S3/ 207.91= .02035 x 2mole FeCl3=.0407 moles FeCl3/ .2M FeCl3= .2035 L x 1000= 203.5 ml
What is the chemical formula for ferrous disulfide?
ferric indicates the iron is +3 as opposed to +2 for ferrous sulfide indicates that there is sulfur with a -2 charge the formula is Fe2S3 two iron ions with a +3 = +6 3 sulfur ions with a -2 = -6 -6+6 = 0
What is the formula for iron IIIsulfide?
Iron has a charge of +3 and Sulfur has a charge of -2, so iron III sulfide is: Fe2S3
Is sulfur and iron an element or a compound or a mixture?
sulfur and iron are elements, sulfur a yellow powder and iron a metal. When mixed together at room temperature they do not react readily and constitute a mixture which can be separated say by using a magnet to attract the iron. Heat them up and a vigorous reaction ensues forming a chemical compound, black iron sulfide, Fe2S3 see link for experimental details
How do you separate sulfur and water?
If you are talking the element sulfur, it is not soluble in water so you can just filter it off. A coffee filter would work. If you are talking the sulfide ion, S-2, you treat it withferric chloride to form the solid Fe2S3, which can then be filtered.
What is n factor in terms of solution?
In cases of particular elements during reactions we see the change is their individual oxidation states.But if we have to calculate the equivalent weight of a species in a particular reaction,we have to find out the n factor for that particular species in the reaction.It is basically the overall exchange of electrons of a species per mole of that species in the reaction. And 1 thing more,n factor can never be calculated for individual atoms. For example:if we have to find out the equivalent weight of Fe2S3 in the reaction Fe2S3 --> FeSO4 + SO2 First v balance the equation which gives Fe2S3 + 502-->2FeSO4 +SO2 Then v find out the oxiadation states of S in d differsnt compounds cos v c that S is the only common element in all.In Fe2S3 The ox.state of s is -2.In FeS04 it's +6 n in SO2 it's +4. So we c the net exchange of electrons per mole of Fe2S3 in d reaction is 2*(+6-(-2))+(4-(-2)) = (2*8)+6 =22 Therefore the n factor of Fe2S3 is 22. So its equivalent weight will be Molecular weight/22.
Formula for iron iii sulfide?
These are the ions and their charges: Fe+3 SO3-2The charges have to add up to zero, so two +3 iron ions cancel out three -2 sulfite:Fe+3 Fe+3 SO3-2 SO3-2 SO3-2Simplify: Fe2(SO3)3
Formula for ironIIIsulfide?
Formula: Fe2S3
