current is the movement of charg carriers (normaly electrons) through a conductive material. the easyest way to think about it is that voltage is like a force pushing on the electrons, and resistance will push back against this. Current is then the result of these two factors. This is where we get the equation voltage=current*resistance. In answer to your question, increasing the circuit resistance will decrease the current in the circuit, as long as the supply voltage stays the same.
If you increase the voltage V, also the current I must go up. R = V / I. The ratio of the resistance stays constant. Scroll down to related links and look at "Ohm's Law".
If resistance is increased, current decreases.
Ohm's Law: current equals voltage divided by resistance.
Ohm's law. I = E/R. The current is directly proportional to the applied EMF and inversely proportional to the resistance of the circuit.
This happens only in pure series circuits, due to increased resistance.
It is halved. coz voltage=current * resistance
In this case current flows from a high voltage to a lower voltage in a circuit.
An electron traveling through the wires and loads of the external circuit encounters resistance.
The circuit becomes a pure resistance circuit where current and voltage are in phase with each others.
If resistance is increased, current decreases. Ohm's Law: current equals voltage divided by resistance.
If resistance is increased, current decreases. Ohm's Law: current equals voltage divided by resistance.
The flow of electrons meets an increased impedance to it's flow.
The flow of electrons meets an increased impedance to it's flow.
If resistance is increased, current decreases. Ohm's Law: current equals voltage divided by resistance.
The voltage drop across each resistance will go up, and the current through the circuit will go down.
When you add resistance to a circuit, current goes down. Ohm's Law: current = voltage divided by resistance.
The resistance is increased, the voltage across each bulb is decreased and the current through the circuit is reduced.
This happens only in pure series circuits, due to increased resistance.
The current at every point in the series circuit becomes slightly less, because the increased length of wire adds slightly more resistance to the loop.
Yes, if the resistance remains constant. Power is voltage times current, and current is voltage divided by resistance, so power is voltage squared divided by resistance. In essence, the power increases as the square of the voltage.
It is halved. coz voltage=current * resistance