The flow of electrons meets an increased impedance to it's flow.
If resistance is increased, current decreases. Ohm's Law: current equals voltage divided by resistance.
If resistance is increased, current decreases. Ohm's Law: current equals voltage divided by resistance.
The flow of electrons meets an increased impedance to it's flow.
If resistance is increased, current decreases. Ohm's Law: current equals voltage divided by resistance.
The voltage drop across each resistance will go up, and the current through the circuit will go down.
When you add resistance to a circuit, current goes down. Ohm's Law: current = voltage divided by resistance.
The resistance is increased, the voltage across each bulb is decreased and the current through the circuit is reduced.
This happens only in pure series circuits, due to increased resistance.
The current at every point in the series circuit becomes slightly less, because the increased length of wire adds slightly more resistance to the loop.
Yes, if the resistance remains constant. Power is voltage times current, and current is voltage divided by resistance, so power is voltage squared divided by resistance. In essence, the power increases as the square of the voltage.
It is halved. coz voltage=current * resistance
Be a little more specific. How low of a current value are you talking about? What does the circuit look like? And what components are a part of the circuit? Possibly, depending on the circuit, nothing extreme happens. You may get increased heat in the circuit due to more resistance. There are a lot of factors to weigh to answer this question...