It depends upon the amount of strong acid that you are using.... in a titration process the pH value initially starts off basic in the beaker.. and doesn't change rapidly until all of the base has reacted with the acid to from water and precipitate ... after all of the weak base has reacted with the acid.. the final PH value is in the acid range i.e 1-7
A pH OF 7
It should be pH 7 provided they are the same molare amounts of NaOH and HCl. If they are thne same weights, the pH will not be 7
It would be basic because bases pick up hydrogen ions. the OH picks up the H in HCl making it H20 and producing NaCl
NaCl -> Na+ OH
HCl-> H+ Cl
Equal quantities of the same thing will give you the same pH.
The water salt solution is neutral.
7
It will be a neutralization reaction and the products will be NaCl and H2O
KOH + HCl = KCl + H2O
(C2H5)3N + HCl = (C2H5)3N+Cl-
HCl or hydrochloric acid will react with NaOH (sodium hydroxide) in a netralisation reaction. HCl is a strong acid and NaOH is a strong base or alkalai. The resultant solution will be warm/hot due to the exothermic reaction taking place. This is an aggressive reaction if the materials are concentrated. HCl + NaOH --> H2O + NaCl
HCl + NaOH -----> NaCl + H2O
It will be a neutralization reaction and the products will be NaCl and H2O
KOH + HCl = KCl + H2O
(C2H5)3N + HCl = (C2H5)3N+Cl-
HCl or hydrochloric acid will react with NaOH (sodium hydroxide) in a netralisation reaction. HCl is a strong acid and NaOH is a strong base or alkalai. The resultant solution will be warm/hot due to the exothermic reaction taking place. This is an aggressive reaction if the materials are concentrated. HCl + NaOH --> H2O + NaCl
HCl + NaOH -----> NaCl + H2O
Yes, species have traded partners and the chemical compositions have changed. A strong acid and a strong base have undergone a neutralization reaction and produced a salt( actually two species in solution ) and water.
When equal volumes of 1 M HCl and 1 M NaOH are mixed, a neutralization reaction will occur. Here's why: HCl is an acid, meaning it donates protons (H+). NaOH is a base, meaning it accepts protons. When these two solutions are mixed, the H+ ions from the HCl react with the OH- ions from the NaOH to form water (H2O). This can be represented by the following chemical equation: HCl + NaOH → NaCl + H2O This reaction is called a neutralization reaction because it results in a neutral solution (pH close to 7). In this case, the products are sodium chloride (NaCl) and water. Here are some additional points to note: Since the volumes and concentrations of the HCl and NaOH solutions are equal, all the H+ and OH- ions will be consumed in the reaction, resulting in a complete neutralization. The final solution will have a pH close to 7, but it might be slightly acidic or basic depending on the presence of any excess reactant ions. I hope this explanation helps! Let me know if you have any other questions.
-55.8 KJ/mol
Nats.
Potassium chloride and water result from this reaction: KOH + HCl = KCl + H2O
HCL 2N solution is prepared by diluting it in a one to five ratio with water. It is not necessary to provide an outside force such as heat or pressure. Simple mixing with complete the dilution.
neutralization reaction