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n=(360/a) - 1 where n - the number of images; a- the angle between the mirrors. so : n=(360/45) - 1 n=8-1 n=7

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Q: If you put two hinged flat mirrors at forty five degrees and put an object between them how many images of the object would there be?
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What will happen if you put an object between two hinged mirrors and make the angle between them smaller?

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The answer depends on the angle between the mirrors. The distance between the mirrors does not, in theory, make any difference. If the angle between the mirrors is x degrees, then the theoretical number of images is (360/x)- 1 which is rounded down. In practice, minor defects in the mirrors, refraction, total internal refraction, absorptions, scattering etc will reduce the number of images.The answer depends on the angle between the mirrors. The distance between the mirrors does not, in theory, make any difference. If the angle between the mirrors is x degrees, then the theoretical number of images is (360/x)- 1 which is rounded down. In practice, minor defects in the mirrors, refraction, total internal refraction, absorptions, scattering etc will reduce the number of images.The answer depends on the angle between the mirrors. The distance between the mirrors does not, in theory, make any difference. If the angle between the mirrors is x degrees, then the theoretical number of images is (360/x)- 1 which is rounded down. In practice, minor defects in the mirrors, refraction, total internal refraction, absorptions, scattering etc will reduce the number of images.The answer depends on the angle between the mirrors. The distance between the mirrors does not, in theory, make any difference. If the angle between the mirrors is x degrees, then the theoretical number of images is (360/x)- 1 which is rounded down. In practice, minor defects in the mirrors, refraction, total internal refraction, absorptions, scattering etc will reduce the number of images.


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