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Balanced equation:

LiOH + HBr ---> LiBr + H₂O

Here, we aim to convert the mass of LiOH to mass of LiBr. In this formula, the product (LiBr) takes x, and the reactant (LiOH) takes y. Here's how it goes. (? = coefficient in the balanced equation)

mass of x = (mole of y) * (? mol x / ? mol y) * (molar mass of x)

mass of LiBr = (10 g / 23.95 g/mol) * (1 mol LiBr / 1 mol LiOH) * (86.85 g/mol LiBr)

mass of LiBr = 36.3 g (Answer)

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12y ago
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10y ago

mol of LiOH = 10g LiOH/ 23.949g/mol LiOH

= 0.418 mol LiOH

mol of LiBr = 1/1 * 0.418

= 0.418 mol LiBr

mass of LiBr = 0.148 mol/ 86.845 g/mol

= 36.301 g LiBr

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15y ago

There are 2.85 grams in a dime

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Q: Lithium hydroxide reacts with hydrobromic acid to produce lithium bromide and water If you start with then grams of lithium hydroxide how many grams of lithium bromide will be produced?
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