The velocity is zero when t=v0/g. This comes from velocity of the ball is v=v0-gt, where v0 is the velocity which the ball is thrown with, the initial velocity. The balls v velocity is the initial velocity v0 - the gravity velocity gt. when the real velocity is zero v= v0-gt=0. solving this for t gives when the velocity is zero.
Acceleration is a vector quantity, so if you can get the various vectors to "cancel out", then you can experience the situation described.
One way would be to be inside a hollow spherical shell. There is no acceleration due to gravity in the shell, because it all "cancels out". You might still experience gravity due to masses outside the shell, but none from the shell itself, and if you can locate it far enough from other masses then the contribution will be negligible.
Right before it starts to fall
A the highest point its velocity will be zero.
If it is thrown at an angle, at the top of its path, its vertical velocity will be zero, however its horizontal velocity will be the same as its initial horizontal velocity minus whatever loss in speed as a result of air friction at that point. We won't know what that is without more information.
"Uniform velocity" means zero acceleration, that is, constant speed in a straight line.rate of change of velocity is zero
Zero.
A simple example is a ball tossed into the air. When the ball reaches its apex -- its highest point -- its instantaneous velocity is zero. If we assume that up is the positive direction, the ball's velocity is positive when it is initially tossed into the air, but it slows immediately. That is, its velocity becomes less positive until it reaches zero velocity. After that point, the velocity becomes increasingly negative (because down is the negative direction). Until the ball returns to earth and reaches the height at which it was initially thrown, its average velocity is non-zero. If the ball is allowed to hit the ground, its average velocity will be slightly negative, which is still non-zero. But it still had an instant -- at its apex -- when its velocity was zero.
Throwing a ball straight up in the air. It will reach some peak where the velocity is zero, but the acceleration due to gravity is a constant -9.8m/s^2.
A the highest point its velocity will be zero.
The initial velocity is zero. In most basic physics problems like this one the initial velocity will be zero as a rule of thumb: the initial velocity is always zero, unless otherwise stated, or this is what you are solving for Cases where the initial velocity is not zero examples a cannon ball is shot out of a cannon at 50 mph a ball is thrown from at a speed of 15 mph etc
If it is thrown at an angle, at the top of its path, its vertical velocity will be zero, however its horizontal velocity will be the same as its initial horizontal velocity minus whatever loss in speed as a result of air friction at that point. We won't know what that is without more information.
"Uniform velocity" means zero acceleration, that is, constant speed in a straight line.rate of change of velocity is zero
Zero.
Yes. An example of this would be a ball thrown straight up; at the very peak of its travel, it's not moving either up or down and therefore has an instantaneous velocity of zero.
A simple example is a ball tossed into the air. When the ball reaches its apex -- its highest point -- its instantaneous velocity is zero. If we assume that up is the positive direction, the ball's velocity is positive when it is initially tossed into the air, but it slows immediately. That is, its velocity becomes less positive until it reaches zero velocity. After that point, the velocity becomes increasingly negative (because down is the negative direction). Until the ball returns to earth and reaches the height at which it was initially thrown, its average velocity is non-zero. If the ball is allowed to hit the ground, its average velocity will be slightly negative, which is still non-zero. But it still had an instant -- at its apex -- when its velocity was zero.
both the magnitudes and the directions of the initial and final velocities are the same.
In that case, the velocity is zero.
Yes, but only for a single instant in time. When you throw a golf ball or a rock straight up, it has the constant downward acceleration of gravity from the moment it leaves your hand, but its velocity is certainly not constant. The velocity steadily decreases until the peak of the toss, and then it switches from upward to downward velocity. At the very peak, the velocity is zero for an instant.
If a ball is thrown horizontally from a window on the second floor of a building, the vertical component of its initial velocity is zero.