The velocity is zero when t=v0/g. This comes from velocity of the ball is v=v0-gt, where v0 is the velocity which the ball is thrown with, the initial velocity. The balls v velocity is the initial velocity v0 - the gravity velocity gt. when the real velocity is zero v= v0-gt=0. solving this for t gives when the velocity is zero.
If it is thrown at an angle, at the top of its path, its vertical velocity will be zero, however its horizontal velocity will be the same as its initial horizontal velocity minus whatever loss in speed as a result of air friction at that point. We won't know what that is without more information.
The ball has an instantaneous velocity of zero at the highest point of its trajectory. This is because at that point, the ball changes direction from going up to coming down, causing its velocity to momentarily be zero before increasing in the opposite direction.
The initial velocity of a dropped ball is zero in the y (up-down) direction. After it is dropped gravity causes an acceleration, which causes the velocity to increase. F = ma, The acceleration due to gravity creates a force on the mass of the ball.
The vertical component of the initial velocity of the ball thrown horizontally from a window is zero. The ball's initial velocity in the vertical direction is influenced only by the force of gravity, not the horizontal throw.
A simple example is a ball tossed into the air. When the ball reaches its apex -- its highest point -- its instantaneous velocity is zero. If we assume that up is the positive direction, the ball's velocity is positive when it is initially tossed into the air, but it slows immediately. That is, its velocity becomes less positive until it reaches zero velocity. After that point, the velocity becomes increasingly negative (because down is the negative direction). Until the ball returns to earth and reaches the height at which it was initially thrown, its average velocity is non-zero. If the ball is allowed to hit the ground, its average velocity will be slightly negative, which is still non-zero. But it still had an instant -- at its apex -- when its velocity was zero.
Throwing a ball straight up in the air. It will reach some peak where the velocity is zero, but the acceleration due to gravity is a constant -9.8m/s^2.
The initial velocity is zero. In most basic physics problems like this one the initial velocity will be zero as a rule of thumb: the initial velocity is always zero, unless otherwise stated, or this is what you are solving for Cases where the initial velocity is not zero examples a cannon ball is shot out of a cannon at 50 mph a ball is thrown from at a speed of 15 mph etc
If it is thrown at an angle, at the top of its path, its vertical velocity will be zero, however its horizontal velocity will be the same as its initial horizontal velocity minus whatever loss in speed as a result of air friction at that point. We won't know what that is without more information.
Yes. An example of this would be a ball thrown straight up; at the very peak of its travel, it's not moving either up or down and therefore has an instantaneous velocity of zero.
The ball has an instantaneous velocity of zero at the highest point of its trajectory. This is because at that point, the ball changes direction from going up to coming down, causing its velocity to momentarily be zero before increasing in the opposite direction.
The initial velocity of a dropped ball is zero in the y (up-down) direction. After it is dropped gravity causes an acceleration, which causes the velocity to increase. F = ma, The acceleration due to gravity creates a force on the mass of the ball.
The vertical component of the initial velocity of the ball thrown horizontally from a window is zero. The ball's initial velocity in the vertical direction is influenced only by the force of gravity, not the horizontal throw.
A simple example is a ball tossed into the air. When the ball reaches its apex -- its highest point -- its instantaneous velocity is zero. If we assume that up is the positive direction, the ball's velocity is positive when it is initially tossed into the air, but it slows immediately. That is, its velocity becomes less positive until it reaches zero velocity. After that point, the velocity becomes increasingly negative (because down is the negative direction). Until the ball returns to earth and reaches the height at which it was initially thrown, its average velocity is non-zero. If the ball is allowed to hit the ground, its average velocity will be slightly negative, which is still non-zero. But it still had an instant -- at its apex -- when its velocity was zero.
The ball's velocity changes to 0m/s and the boy's stays the same.
At the highest point of a ball's vertical motion, its velocity is zero. This is because the ball briefly comes to a stop before falling back down due to gravity.
The highest point is the point where the ball's velocity transitions from upward to downward. At that instant, the ball's speed, velocity, momentum, and kinetic energy are all exactly zero.
Yes, but only for a single instant in time. When you throw a golf ball or a rock straight up, it has the constant downward acceleration of gravity from the moment it leaves your hand, but its velocity is certainly not constant. The velocity steadily decreases until the peak of the toss, and then it switches from upward to downward velocity. At the very peak, the velocity is zero for an instant.