If it's a 100 W bulb that does not say everything about it. It could be a 12 v, 24 v, 120 v or a 230 v bulb, or other voltage. Look on the case or the packet.
The amps drawn by a 65 watt light bulb should be 65/120 or 0.54167. This fraction of an ampere may be restated as 541.67 milli-amps.
A 65 Watt incandescent light bulb should draw 65W/120V = 541.67mA
If a light bulb is rated at 60 Watts, the voltage will depend on the specific type of bulb. For a typical incandescent bulb, the voltage would be around 120 volts. However, for an LED or CFL bulb, the voltage could be different, such as 120 volts or 240 volts.
A 60 watt light bulb typically draws 0.5 amps from a 120-volt power source. This is calculated by dividing the wattage (60 watts) by the voltage (120 volts).
A 60 watt bulb at 12 volts will pull 5 amps of current.
Yes, a 103 volt source will light a 60 watt light bulb. The relationship of the bulb's wattage output at a lower voltage, as to the normal voltage that the bulb is rated to operate on, the light output will be lower.
The voltage isn't decided by the lamp, but by the supply the lamp is hooked up to.
Amps x volts = watts So, assuming you are running on 110 volt line, the answer is 65 watts/110 volts=.591 amps.
To calculate the amperage of a 40-watt bulb, you need to use the formula: Amps = Watts / Volts. If the bulb operates at 120 volts (standard for US households), the amperage will be 0.33 amps (40 watts / 120 volts).
Watts = Volts X Amps. Amps=Watt / Volts. So, with a 240V mains, a 60W bulb draws 0.25amps. On a 12 system (car/auto) a 60W bulb draws 5 amps. On a 110V mains, a 60W bulb draws .55 Amps.
Watts = Volts x Amps x Power Factor. An incandescent light bulb is a resistive load so PF = 1. ANSWER: = 1/2 Amp
Yes, provided the bulb types are compatible with the 400 watt ballast.