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In a certain balanced three-phase system each line current is 5 a and each line voltage is 220 v what is the approximate real power if the power factor is 0.7?
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∙ 11y ago
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∙ 11y ago
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Why doesn't any current flow through the galvanometer in a balanced Wheatstone bridge?
There is no current flow through the galvanometer in a balanced Wheatstone bridge because, in the balanced state, the voltage on both terminals of the galvanometer is the same. Since the voltage differential in zero, there can be no current.
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Line current = 1.732 x Phase CurrentCommentOnly for balanced loads.
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Why doesn't any current flow through the galvanometer in a balanced Wheatstone bridge?
There is no current flow through the galvanometer in a balanced Wheatstone bridge because, in the balanced state, the voltage on both terminals of the galvanometer is the same. Since the voltage differential in zero, there can be no current.
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In a three phase system, if the current in all three phases are same, then it is a balanced system.
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if it is balanced then neutral current is zero (!,e iR=iY=iB).AnswerFor both a balanced and an unbalanced load, the neutral current will be the phasor sum of the line currents.
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In a properly balanced three phase system, there is negligible current on neutral. If there is substantial current on neutral, then the system is not balanced and/or something is wrong.
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Balanced load means no unbalanced currents, so the neutral current should be near zero.
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In delta connection what is formula for phase current?
Line current = 1.732 x Phase CurrentCommentOnly for balanced loads.
In a certain balanced three phase system each line current is 5 a and each line voltage is 220v what is the approximate real power factor is 0.7?
1905 watt's ( the pf hasn't been indicated as leading or lagging) this is wrong. the answer is 1770 W its looking for a symplified answer if you dont know whether its leading or lagging use basic formula 220v * 5a * .7 = watts
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Nothing. The electricity company balanced the feeds out of each substation so that the returning current is balanced. So the returning current is just an overall part of the grid.
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