1905 watt's ( the pf hasn't been indicated as leading or lagging) this is wrong. the answer is 1770 W its looking for a symplified answer if you dont know whether its leading or lagging use basic formula 220v * 5a * .7 = watts
You'll have to rephrase your question -as it is, it doesn't make sense.
Balanced Star (Wye) Connected Systems:Line Voltage = 1.732 x Phase VoltageLine Current = Phase CurrentBalanced Delta Connected Systems:Line Voltage = Phase VoltageLine Current = 1.732 x Phase Current
Yes, but only for balanced loads (current in all three phases the same value). The voltage value used is the phase to phase voltage.
The approximate voltage across the forward-biased base-emitter junction is 0.7 volts.
Voltage is equal to the Current multiplied by the Resistance.Without changing the resistance, increasing the applied voltage in a circuit will increase current flow. There is a simple, direct relationship between voltage and current. Double the voltage, twice the current will flow. Triple the voltage, and the current will triple. As voltage (E) equals current (I) times resistance (R), when resistance is fixed, what happens to voltage will happen to current.
answer is actually voltage
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There is no current flow through the galvanometer in a balanced Wheatstone bridge because, in the balanced state, the voltage on both terminals of the galvanometer is the same. Since the voltage differential in zero, there can be no current.
Balanced Star (Wye) Connected Systems:Line Voltage = 1.732 x Phase VoltageLine Current = Phase CurrentBalanced Delta Connected Systems:Line Voltage = Phase VoltageLine Current = 1.732 x Phase Current
Yes, but only for balanced loads (current in all three phases the same value). The voltage value used is the phase to phase voltage.
Think of Voltage as the pressure and Amperage (current) as flow. If you think of it as pipes with water then the pressure would be voltage, and current would be how much water flows past a certain point in the pipe in a given time.
In common, any application if voltage is increased current will be the small amount. at the same if voltage Decreased current will be increased...AnswerAccording to Ohm's Law, 'the current flowing through a conductor is directly proportional to the applied voltage, provided certain conditions, such as temperature, remain constant'. So if you double the voltage, the resulting current will double; if you halve the voltage, the current will halve.
You can 'block' current ... like with a high series resistance ...but you can't 'block' voltage.
Nothing. The electricity company balanced the feeds out of each substation so that the returning current is balanced. So the returning current is just an overall part of the grid.
In star the voltage from line to neutral is 1/sqrt(3) times the nominal voltage, while the load current equals the line current. In delta the voltage between lines is the nominal voltage, while the load current is 1/sqrt(3) times the line current (for a balanced load). So a delta load needs 3 times the resistance compared to a star load of the same power.
If you have a simple circuit. For eg: One voltage source and one resistor, then the voltage of the circuit will always remain the same, the current however will decrease following Ohms' Law V=I*R. If we have a current source instead of a voltage source, we are forcing the current to be a certain value so if we increase the resistor value the current will remain the same but the voltage will increase.
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)