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Q: In a hydraulic system thr force exerted on the large piston is?
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What will happen to the size of the force of the exerted by a hydraulic system if the output piston has a smaller area?

yes have a smaller area:)


How do you calculate force for hydraulics?

You get the force exerted by a hydraulic piston by taking the pressure times the surface area of the piston.


Why is force exerted on a small piston multiplied when it acts on a larger piston?

A hydraulic system multiplies force by applying the force to a small surface are. The increase in pressure is then transmitted to another part of the confined fluid, which pushes on a larger surface area


A force of 1000n is exerted on piston 1 what will be exerted on piston 2?

If this is about a hydraulic system, same pressure acts through out the fluid. Take, A = cross sectional area (area normal to force) of piston 1 B = "" "" "" of piston 2 F2 = Force on 2nd piston So, pressure = 1000/A = F/B Therefore, F = (1000 X B/A ) N (The force depends on the area ratio)


Why is force exerted on a small piston multiplied when it acts on a larger pistion?

Suppose the smaller piston was 1 square cm and the large piston was 7 square cm. If you pushed on the small piston, the force would be multiplied 7 times on the large piston. The Hydraulic System is a system that uses liquids to transmit pressure and multiply force in a confined fluid. Hope this helped. (:


How is a force multiplied in a hudraulic system?

In a hydraulic system, the force on the applying piston is multiplied by the reciprocal of the area of the piston, to find pressure which is multiplied by the piston area.


Calculate the force output by the larger piston of a hydraulic lift when a force of 700 n is exerted on the smaller piston the areas of the two pistons are 20 cm squared and 950 cm squared?

33,250.


What is the force exerted on the right piston?

Katie is awesome


A hydraulic lift exerts 7000 N of force on a piston with an area of 0.4 m2 the piston can only support 16000 Pa of pressure How much Pressure is exerted by the truck on the piston?

A.2800 Pa b.6400 Pa c.17,500Pa


What would happen if you doubled the area of the piston on the right side of the hydraulic system?

Double the force applied by that piston and half the speed that it moves.


Hydraulic cylinder retract force on piston with rod size reduced by half at piston end?

http://www.engineeringtoolbox.com/hydraulic-force-calculator-d_1369.html


How is energy conserved in a Hydraulic system?

The consertvation of energy in a hydraulic system could be understood by the formular (ENERGY = FORCE x DISTANCE) that represents mechanical energy. Now the hydraulic system consist mainly of two set of pistons which are the master where the energy is applied to the system and the slave where energy leaves the system to the load. Irrespective of the force diffence of the master piston and the slave piston, they will always give the same value when multiplied with distance moved by their respective pistons. This prove that the difference in forces experienced or distance moved by the master and slave piston did not alter the amount of energy in the hydraulic system since energy can be seen as force x distance ;)