Want this question answered?
yes have a smaller area:)
You get the force exerted by a hydraulic piston by taking the pressure times the surface area of the piston.
In a hydraulic system, the force on the applying piston is multiplied by the reciprocal of the area of the piston, to find pressure which is multiplied by the piston area.
Katie is awesome
A.2800 Pa b.6400 Pa c.17,500Pa
yes have a smaller area:)
You get the force exerted by a hydraulic piston by taking the pressure times the surface area of the piston.
A hydraulic system multiplies force by applying the force to a small surface are. The increase in pressure is then transmitted to another part of the confined fluid, which pushes on a larger surface area
If this is about a hydraulic system, same pressure acts through out the fluid. Take, A = cross sectional area (area normal to force) of piston 1 B = "" "" "" of piston 2 F2 = Force on 2nd piston So, pressure = 1000/A = F/B Therefore, F = (1000 X B/A ) N (The force depends on the area ratio)
Suppose the smaller piston was 1 square cm and the large piston was 7 square cm. If you pushed on the small piston, the force would be multiplied 7 times on the large piston. The Hydraulic System is a system that uses liquids to transmit pressure and multiply force in a confined fluid. Hope this helped. (:
In a hydraulic system, the force on the applying piston is multiplied by the reciprocal of the area of the piston, to find pressure which is multiplied by the piston area.
33,250.
Katie is awesome
A.2800 Pa b.6400 Pa c.17,500Pa
Double the force applied by that piston and half the speed that it moves.
http://www.engineeringtoolbox.com/hydraulic-force-calculator-d_1369.html
The consertvation of energy in a hydraulic system could be understood by the formular (ENERGY = FORCE x DISTANCE) that represents mechanical energy. Now the hydraulic system consist mainly of two set of pistons which are the master where the energy is applied to the system and the slave where energy leaves the system to the load. Irrespective of the force diffence of the master piston and the slave piston, they will always give the same value when multiplied with distance moved by their respective pistons. This prove that the difference in forces experienced or distance moved by the master and slave piston did not alter the amount of energy in the hydraulic system since energy can be seen as force x distance ;)