Graduated
Not if the solution contained only glucose and water.
A 30% glucose solution is purely glucose and water, though it is actually impossible to keep other contaminants out of it. To create a 30% solution of glucose, you take a fixed volume of water and add 30% of that value of glucose to the water. The amount of glucose is in grammes. For example, 3g of glucose would be added to 10ml of water.
you will be given glucose you will be given glucose
Water will diffuse from solution B to solution A
One way is by polarimeter; glucose and sucrose rotate polarized light in opposite directions. This is assuming your materials are of biological origin and therefore consist of the D-forms of both; if they're synthetic, then all bets are off.
15 litres
No. For the physical formula ratio, of [solute:solvent] to be the same, you would have to use twice as much glucose as sucrose, to make the solution; because sucrose is a disaccharide. But, when preparing the solution, the actual weight used will be approximately the same. You have a solution, with solute sucrose, at 1C ratio. Weighing the same amount of glucose (in grams), will make a solution of 2C ratio. General expression is Glucose:Sucrose::2:1.
I don't think you can. The maximum solubility of glucose in water is 91% w/v. That would mean dissolving 91g of glucose in 100ml of water. for a 100% solution you would need to dissolve 100g in 100ml, and you cant do it under normal conditions.
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
Let's say the total solution is 100 liters. 50 of the liters is glucose and 50 is water. We want to make the 50 glucose equal to 10% of the total solution. For that to happen, we need to make the total solution 500 liters (50 of the 500 would be a 10% solution). So we add 400 liters of water to the original 100 liter (50/50) solution. Take the total number of units and multiply by 4. Add that much in water.
A Bunsen Burner
A measuring tape.