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In a lamp circuit the voltage drop is the result ofwhat?

Updated: 8/17/2019
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13y ago

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Let me explain the concept of a voltage drop and let us forget the lamp for now. Voltage drop is the result of an electrical current flowing through an resistance.

Ohms Law state that:

V = I x R

R = Resistance in ohms

I = Electrical current in ampere

V = Potential difference in voltage or in our example we can call it the voltage drop

Regardless of where a resistance is found in an electric circuit. The product of its resistance and the current flowing through it will results in a voltage drop across the resistance.

If I have a 22ohm resistor in a circuit and on any given instant a 2 ampere current is flowing through it. The voltage across the resistor is 44V. Thus 44V is the voltage drop regardless of what the supply voltage is.

But not only resistors has resistance, in fact all electrical components have some form of resistance even the conductors, cables, connectors and switches.

Other common examples of resistances are:

*Internal resistance of batteries

*Light bulbs

*Electric motors

*Electromagnets

They all have resistance, any conductor or semiconductor what is practically used will have a resistance to it and can therefore have a voltage drop if electrical current flow through it.

The methods used in this example should never be attempted in AC circuits because the effects of magnetic fields and electric field may produce different results. Pure resistance only apply to DC circuits. Sufficient inductive and capacitive reactances especially in equilibrium may produce dangerous voltages in AC circuits.

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Q: In a lamp circuit the voltage drop is the result ofwhat?
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