Voltage and current will be in phase for a purely resistive load. As a load becomes more inductive or capacitive, the phase angle between voltage and current will increase.
When an alternating voltage is applied to a purely resistive circuit, the resulting current is in phase with the voltage.
The phase angle between voltage and current in a purely resistive circuit is zero. Voltage and current are in phase with each other.
'A' and 'C' are saying exactly the same thing. The correct choice is 'D'. The complex impedance of a purely resistive circuit is purely real. Since there is no reactance, there is no phase shift, so the power factor is ' 1 ', KVA = KW, KVAR = 0, etc.
In a pure resistive circuit the voltage and current are in phase. In an inductive circuit they are fro zero to 180 degrees out of phase. If they are in phase the Power Factor is 1 and 180 degrees the PF is zero. The exact amount of the phase difference depends on the specific circuit.
The phase angle between voltage and current in a purely inductive circuit, under ideal circumstances where there is no resistance at all, is 90 degrees.
When an alternating voltage is applied to a purely resistive circuit, the resulting current is in phase with the voltage.
The phase angle between voltage and current in a purely resistive circuit is zero. Voltage and current are in phase with each other.
both have to confront with resistance.
in passive circuit it depends on the type of load 1. if the load is purely resistive the voltage and current will be in phase 2.if the load is purely inductive the current lags the voltage by 90 dgree 3.if the load is purely capacitive the currents leads the voltage by 90 degree
'A' and 'C' are saying exactly the same thing. The correct choice is 'D'. The complex impedance of a purely resistive circuit is purely real. Since there is no reactance, there is no phase shift, so the power factor is ' 1 ', KVA = KW, KVAR = 0, etc.
In a pure resistive circuit the voltage and current are in phase. In an inductive circuit they are fro zero to 180 degrees out of phase. If they are in phase the Power Factor is 1 and 180 degrees the PF is zero. The exact amount of the phase difference depends on the specific circuit.
If the current rises and falls with the voltage, then the two are said to be 'in phase'; this occurs in a purely-resistive circuit. For inductive or capacitive circuits, the current either lags or leads the voltage.
A: purely resistive
The power factor of a purely resistive circuit is 1.0.
It depends on the nature of the circuit. In a purely-resistive circuit, the current would rise immediately because resistance merely limits its value, it doesn't oppose any change in current. But in a resistive-inductive circuit, for example, the inductive component opposes any change in current, so the current will rise more gradually.
It really does depend upon what you mean by 'shift'. For purely-resistive circuits, the load current is in phase with the supply voltage. For reactive circuits, the load current will lead or lag the supply voltage; for capacitive-resistive circuits, the load current leads, whereas for inductive-resistive circuit, the load current lags. You can change the angle by which the current leads or lags (the 'phase angle') by changing the amount of resistance or reactance.
I'm sure I can answer this if given more details, what circuit? current is determined by voltage and impedence(resistance) in a purely resistive circuit it is pretty basic, in alternating voltage circuits the impedence is dependent on the frequency of the voltage/current. inductors and capacitors are designed into a/c circuits to force the load to behave like a resistive circuit which boils down to how much voltage divided by how much resistance you have, 120 volts divided by 10 ohms equals 12 amps. in a parallel circuit it works pretty much the same way voltage placed on the resistor divided by its resistance equals the current flowing through that leg. more details please.