It would be around 50%.
If an individual is of the dominant phenotype, its genotype can be either AA or Aa (letter A picked for demonstration's sake). To do a good test cross, we have to be able to unambiguously tell which one of the genotypes the individual is. The best test cross would be conducted with a homozygous recessive (aa) individual. This way, if the cross generates 100% dominant phenotype, then the original individual was homozygous dominant. If the cross generates 50% dominant and 50% recessive phenotype, then the original individual was heterozygous.
A cross between two homozygous parents will form a 100 percent chance of a heterozygous offspring. One homozygous parent must have the dominant allele, and the other must have the recessive allele. So, if the circumstances are correct, these characteristics will make for a 100 percent chance of a heterozygous offspring.
The offspring would have a 50% chance of being heterozygous and showing the dominant trait and a 50% chance of being homozygous for the recessive trait.
If both oompahs are heterozygous (Oo), there are three possible genotypes that would result in offspring with orange faces: OO, Oo, and oO. Therefore, 75% of the offspring from this cross would have orange faces.
Out of the 240 offspring, approximately 60 would be homozygous (25% of 240). This is because when two heterozygous plants are crossed (Aa x Aa), the Punnett square shows that 25% of the offspring will be homozygous dominant (AA), 50% will be heterozygous (Aa), and 25% will be homozygous recessive (aa).
Not necessarily. The offspring being alike and resembling the organism being tested is an indication of the parent being homozygous for the traits being tested, but it is not a definitive proof. Further tests or observations would be needed to confirm the parent's genotype.
To determine if a plant is homozygous or heterozygous, you would need to test cross it with a homozygous recessive plant. If the offspring show the recessive trait, the original plant is heterozygous; if all offspring show the dominant trait, the original plant is homozygous.
There is a 25% chance (1 in 4) that the offspring will be homozygous for the trait. This is because when both parents are heterozygous (Aa), they can pass on either the dominant allele (A) or the recessive allele (a) to their offspring, resulting in a 1 in 4 chance of the offspring receiving the recessive allele from both parents and becoming homozygous (aa) for that trait.
In the case of selfing an Rr individual - which is heterozygous - you would expect 50% of the offspring to be heterozygous (Rr), as each parent contributes one allele to the offspring. Each allele has a 50% chance of being passed on.
Tt
To determine the genotype of an individual who is heterozygous for a trait, you would need to perform a genetic cross with a homozygous recessive individual. By observing the phenotypes of the offspring, you can deduce the genotype of the heterozygous individual. This can help determine if the heterozygous individual is carrying one dominant and one recessive allele.
Half of the offspring, or 100 rabbits, would be expected to be white when offspring from a heterozygous brown rabbit and a white rabbit are produced. This is due to the dominant-recessive inheritance pattern where brown is dominant and white is recessive.