If we assume "S" is the short haired trait, it could be 1 of 2 things. The first is "Ss". The pig still carries the long hair recessive gene, but it is not shown in the phenotype. The second is "SS". The pig does not carry the long hair gene and will probably not pass it onto the offspring. The second possibility is most likely going to happen with a purebred, but the guinea pig could still have gotten a recessive "s" from a parent - short haired or not.
the babys should have short hair with long starands or patches on the rump with long hair.
Ss (big s, little s)
I think it is GG or Gg.
black
50 percent
The phenotype of the black guinea pig is black, and the pheno type of the white guinea pig is white.
You could try breeding it with a homozygous recessive partner (hh) Lets assume that you breed the original mystery rabbit with an hh recessive partner, and they have 10 offspring. If the original rabbit is homozygous dominant, it would be HH + hh, which would give all 10 the offspring Hh genotypes, which would give them the dominant hair color. If it was heterozygous dominant, it would be Hh + hh, which would lead to either Hh or hh offspring. This means that in theory, 5 would be dominant colored while the other 5 would not be.
In genetics, you can either have a dominant allele (A) or a recessive allele (a). Being homozygous means that you have both of either a dominant or a recessive allele (ie you are either AA or aa). If the trait is a recessive trait, then you need to have it be homozygous recessive in order to express that trait. Hope this was helpful! :-)
100% because BB is dominant over bb and all the crosses make Bb
BbxBb = 25% homozygous BB; 50 % heterozygous Bb, and 25% homozygous recessive bb.
If a horse is homozygous dominant EE, he is black. Homozygous recessive ee, he is red. A black EE horse that is homozygous dominant for the Agouti gene (AA) will be a bay horse. If that same EE black were homozygous recessive for aa, then he would still appear all black. The Agouti gene does not effect a red ee horse's phenotype.
The phenotype will show the dominant trait. All dominant traits mask recessive ones; If the genotype is heterozygous (One dominant and one recessive) the organism's phenotype will be dominant.
The phenotype of the black guinea pig is black, and the pheno type of the white guinea pig is white.
Three. Each homozygous genotype will have one phenotype each, and the heterozygote will have a third. Unlike incomplete dominance, where the heterozygote's phenotype is a blending of the two homozygous ones (i.e. crossing homozygous red and homozygous white snapdragons results in pink heterozygotes), codominance means the phenotype for each allele is seen in the heterozygote. An example can be seen in the Andalusian fowl. The two homozygotes have black and white plumage respectively, but heterozygotes appear blue, due to the presence of a fine mosaic of black and white areas (no blending).
Genotype is the coded for traitPhenotype is the visible characteristicSo in the case where both parents had heterozygous dominant Brown eyes (Bb - big B for brown, dominant gene; little b for blue recessive gene); it is possible for the child to have blue eyes, by being homozygous recessive (bb).However this is an educated guess, as your question does not make sense.
Phenotype: Black Bear x Brown Bear Genotype: BB x bb Possible gametes: B B b b Possible B B crosses: b Bb Bb b Bb Bb Phenotype of offspring: Only Black bears
If both parents have the same phenotype, but the offspring did not share that phenotype, then it is likely that the parents have a dominant phenotype, but the offspring has a recessive phenotype, which means that the offpring's genotype would be homozygous recessive, and it's parents' genotypes would be heterozygous. For example, the parents may both have the genotype Bb, which gives them black fur. Approximately 25% of their offspring should have the genotype bb, which gives them the phenotype of white fur.
If both parents have the same phenotype, but the offspring did not share that phenotype, then it is likely that the parents have a dominant phenotype, but the offspring has a recessive phenotype, which means that the offpring's genotype would be homozygous recessive, and it's parents' genotypes would be heterozygous. For example, the parents may both have the genotype Bb, which gives them black fur. Approximately 25% of their offspring should have the genotype bb, which gives them the phenotype of white fur.
Bb The phenotype is what the individual looks like. The genotype is the genetic material at the site that can be passed on even if it isn't expressed. For example: Animal with black hair bb (can only pass the black characteristic on to it's offspring because it is homozygous recessive). It is phenotypically black. An animal with red hair can be Bb or BB. Bb is heterozygous and the animal is phenotypically red. BB is homozygous dominant for red and the animal is phenotypically red. More information than requested but an explanation none the less.
If the allele is dominant, you only need one copy for it to be expressed in the phenotype (you have TWO alleles for each trait) If the allele is dominant, you only need one copy for it to be expressed in the phenotype (you have TWO alleles for each trait)
Because the parent with the homozygous alleles for the dominant trait can only pass on that dominant allele to its offspring and the dominant allele, if present, is always expressed.
Well considering that chestnut is recessive the foal most likely would be black, although it could be possible to get a bay foal.