H2S (g) + 2 O2 (g) --> H2SO4 (l)
1 mole + 2 mole --> 1 mole
You will need 2 moles of O2
The value is 3,45 moles oxygen.
Balanced equation: 2H2S + 302 = 2SO2 + 2H20
4 C3H8 + 20 O2 ---> 12 CO2 + 16 H2O So 20 mol of O2 are needed.
Ca + 2 H2O ------> Ca(OH)2 + H2 so 2 moles of calcium react with 4 moles of water.
2C2H2 + 5O2 ---->4CO2 + 2H2O so 1 mole of acetylene (ethyne) reacts with 2.5 moles of oxygen. Answer 2.5 moles
7.54 mol of K
Balanced equation: 2H2S + 302 = 2SO2 + 2H20
4NH3 + 3O2 -----> 2N2 + 6H2O 4 moles of ammonia react with 3 of oxygen. So 10 moles of ammonia requires 7.5 moles of oxygen.
4 C3H8 + 20 O2 ---> 12 CO2 + 16 H2O So 20 mol of O2 are needed.
.913 moles
Ca + 2 H2O ------> Ca(OH)2 + H2 so 2 moles of calcium react with 4 moles of water.
2C2H2 + 5O2 ---->4CO2 + 2H2O so 1 mole of acetylene (ethyne) reacts with 2.5 moles of oxygen. Answer 2.5 moles
7.54 mol of K
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
The nunber of moles of oxygen is 2,5.
I have already balanced - 2C2H2+5O2->4CO2+2H2O what do I do next? 2 moles acetylene--------------5 moles oxygen O2 7 moles acetylene--------------x moles oxygen O2 x = 7 x 5/2 = 17,5
The answer is 3,375 moles oxygen.
Assuming that all gases in this reaction are at STP, what number of molecules of hydrogen chloride gas are needed to completely react with oxygen to yield 50.00 mL of chlorine