Indicate%20the%20phenotype%20and%20the%20genotype%20percentages%20of%20male%20VV%20and%20female%20Vv
Ex. Genotype = Phenotype AA Pure, no cleft chin Aa Hybrid, no cleft chin AA Pure, cleft chin XX Female XY Male
For the case of the human, an individual with XX genotype is female. Other organisms have different ways of determining sex.
the phenotype is what you see like for example DD is the genotype and homozygous dominant is the phenotype. Another example is phenotype Heterozygous round eyes or in genetic form Rr. Phenotype means what you see and Genotype is the gene. I hope this answers your question
XXY-Klinefelter syndromePeople with Klinefelter syndrome are also tall male phenotype. They are sterile, may show mild mental impairment, and may develop enlarged breast because of the extra X chromosome.
Albinism is a sex-linked trait. Accordingly, the description of "heterozygous male" doesn't make sense. The sex chromosomes for males are XY, and usually genetic disorders are passed down by the X chromosome (which is the case for albinism). So in the problem, we aren't sure whether the male is XaY or XAY. It would be more helpful to know if the male was albino or not; we would then immediately know his genotype. We can, however, figure out the genotype of the female. Because albinism is recessive, we can deduce that her genotyple is XaXa. But without knowing the male's genotype or phenotype, the offspring percentages cannot be calculated.
If the male parent has genotype AS and the female parent has genotype AA what is the offspring?
The genotype for a male is XY. A female is XX. The 23rd homologous pair is the sex gene that determines this.
These genotypes are determined by a human's 23rd pair of chromosomes. If the subject is female, she has two X's reading XX. If it is male, then his genotype will read XY. There is a 50-50 shot of each. This is because a woman donates one chromosome (she only has two X's so it is inevitable that she will donate an X), and a man donates one of his. If a man donates his 'X' then there will be two X's and the child will be female. If he donates his 'Y' then the child will be male.Male is XY, female is XX. There are, however, other genotypes (XXY, XXX, XO...) and not all people have a phenotype that goes with their genotype.
XX
A male grasshopper's genotype is XO. A female grasshopper's genotype is XX. X represents the presence of a sex chromosome, and O represents the lack of a sex chromosome.
50% probability that the sons produced from this union will be color blind. 50% probability that a son will not have the disease. 50% probability that a daughter will be a carrier of the allele for color blindness. 50% probability that a daughter will not be a carrier. Phenotypically this would be 1male color blind, 1 male not color blind, 1 female carrier and 1 female non-carrier. Assuming that the probability of male and female offspring is identical...this would be 25% of each genotype mentioned above. Based on phenotype, without regard to sex the percentages of normal to colorblind would be 75% to 25% with the 25% displaying the characteristic all being male.
XX