Indicate%20the%20phenotype%20and%20the%20genotype%20percentages%20of%20male%20VV%20and%20female%20Vv
XXY-Klinefelter syndromePeople with Klinefelter syndrome are also tall male phenotype. They are sterile, may show mild mental impairment, and may develop enlarged breast because of the extra X chromosome.
Ex. Genotype = Phenotype AA Pure, no cleft chin Aa Hybrid, no cleft chin AA Pure, cleft chin XX Female XY Male
When a homozygous dominant female (genotype AA) is crossed with a homozygous recessive male (genotype aa), all offspring will inherit one dominant allele from the mother and one recessive allele from the father, resulting in a genotype of Aa for all offspring. The phenotype ratio will show all offspring displaying the dominant trait. Thus, the genotype ratio is 100% Aa, and the phenotype ratio is 100% expressing the dominant trait.
Nondisjunction in an XXX genotype can occur during cell division, leading to an extra X chromosome being present. In this case, the individual will have three X chromosomes instead of the usual two, resulting in a phenotype of a nearly normal female with some potential for developmental and reproductive issues.
the phenotype is what you see like for example DD is the genotype and homozygous dominant is the phenotype. Another example is phenotype Heterozygous round eyes or in genetic form Rr. Phenotype means what you see and Genotype is the gene. I hope this answers your question
a biologically male individual. The XY genotype typically refers to the genetic makeup of males in humans, where X represents one of the sex chromosomes inherited from the mother and Y represents the sex chromosome inherited from the father.
The genotype for a male is XY. A female is XX. The 23rd homologous pair is the sex gene that determines this.
XX
These genotypes are determined by a human's 23rd pair of chromosomes. If the subject is female, she has two X's reading XX. If it is male, then his genotype will read XY. There is a 50-50 shot of each. This is because a woman donates one chromosome (she only has two X's so it is inevitable that she will donate an X), and a man donates one of his. If a man donates his 'X' then there will be two X's and the child will be female. If he donates his 'Y' then the child will be male. Male is XY, female is XX. There are, however, other genotypes (XXY, XXX, XO...) and not all people have a phenotype that goes with their genotype.
XX
These genotypes are determined by a human's 23rd pair of chromosomes. If the subject is female, she has two X's reading XX. If it is male, then his genotype will read XY. There is a 50-50 shot of each. This is because a woman donates one chromosome (she only has two X's so it is inevitable that she will donate an X), and a man donates one of his. If a man donates his 'X' then there will be two X's and the child will be female. If he donates his 'Y' then the child will be male.Male is XY, female is XX. There are, however, other genotypes (XXY, XXX, XO...) and not all people have a phenotype that goes with their genotype.
50% probability that the sons produced from this union will be color blind. 50% probability that a son will not have the disease. 50% probability that a daughter will be a carrier of the allele for color blindness. 50% probability that a daughter will not be a carrier. Phenotypically this would be 1male color blind, 1 male not color blind, 1 female carrier and 1 female non-carrier. Assuming that the probability of male and female offspring is identical...this would be 25% of each genotype mentioned above. Based on phenotype, without regard to sex the percentages of normal to colorblind would be 75% to 25% with the 25% displaying the characteristic all being male.