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50% probability that the sons produced from this union will be color blind.

50% probability that a son will not have the disease.

50% probability that a daughter will be a carrier of the allele for color blindness.

50% probability that a daughter will not be a carrier.

Phenotypically this would be 1male color blind, 1 male not color blind, 1 female carrier and 1 female non-carrier. Assuming that the probability of male and female

offspring is identical...this would be 25% of each genotype mentioned above.

Based on phenotype, without regard to sex the percentages of normal to colorblind would be 75% to 25% with the 25% displaying the characteristic all being male.

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