Just divide the output force by the input force.Just divide the output force by the input force.Just divide the output force by the input force.Just divide the output force by the input force.
25
If you want to work in watts, convert 25dB to a scalling factor: 3dB = 2 x input 10dB = 10 x input 20dB = 100 x input ...25dB = 10 ^ (25/10) = 316.2 x input So the output is 15 Watts x 316.2 = 4.7kW If you want to work in dB, then convert 15 watts to dB: 10 * log |P| = dB = 10*log |15| = 11.76dB so the output is 11.76 + 25 = 36.76dB
25%Take Input - Waste = Differencethen D / I = Effeciencyso, 400000 - 300000 = 100000and 100000 / 400000 = .25 or 25%now ask the teacher next time...Dont answer the question if you are going to get an attitude...
Efficiency = (output/input) x 100 = (80/320) x 100 = 25%
If you want to work in watts, convert 25dB to a scalling factor: 3dB = 2 x input 10dB = 10 x input 20dB = 100 x input ...25dB = 10 ^ (25/10) = 316.2 x input So the output is 15 micro Watts x 316.2 = (4700)/(10^6) = 4.7 milli watts If you want to work in dB, then convert 15 micro watts to dB: 10 * log |P| = dB = 10*log |15 x 10^6| = -48.2dB ***When you have very small (ie negative) dB, it is often referred to in dBm, or 1/1000 of dB ( 30 dBm = 0 dB) so the output is -18.2dBm + 25 = 6.8dBm, or -23.2dB
Since the total number of possible input combinations is 25, which is 32, and since a low on all five inputs is the only condition resulting in a low at the output, the answer is 31.
An input number is a mathematical form to show how numbers change from one number to another for example : number 27 is the input number and the numbers in the machine is -2 x 3 so you first 27-2=25 then 25x3=75 so the output number is 75. By : smart Arusshnavi
2.4MHz 60MHz/25 = 2.4MHz
If you are talking about 4 mA = 0% and 20 mA = 100% then the formula would be a linear equation: y=mx + b y=6.25(x) - 25 y= percentage x=mA ouput So for example put 4 mA in place of x and you get 0% for y and if you use 20 mA in place of x you get 100% for y. You can rewrite the equation if only Percent input is known to find mA output it would be X= (Y + 25)/6.25 this way you input the percent in for (Y) and you have the mA output for X
Out of the 200KJ input, 150KJ isn't usable. The only usable output of themachine is the remaining 50KJ.The efficiency of that machine is 50KJ/200KJ = 25% .It must be pointed out, though, that it all depends on your definition of what isusable and non-usable output. For example, if this machine were labeled as an"Office Space Heater", then the 150KJ of heat would be the usable output, andthe efficiency would have been 75% .
If the waste heat is 15 compared to the total heat input of 20 (ignoring the thousands) this means the heat doing useful work is 5, which represents 25 percent of the total input heat, so this is the efficiency. Waste heat in a car is the sum of the engine cooling losses and the exhaust losses, the rest is converted to mechanical energy which is useful. 25%