25%
Take Input - Waste = Difference
then D / I = Effeciency
so, 400000 - 300000 = 100000
and 100000 / 400000 = .25 or 25%
now ask the teacher next time...
Dont answer the question if you are going to get an attitude...
Assuming the fuel gets turned into heat, kinetic energy and nothing else... (no sound, no vibrations, no light etc)
(2000000 - 1500000) / 2000000 * 100 = 25%
25% is used, the rest (75%) is wasted.
Efficiency is output/input, waste heat is what not going to output.
Input = Output + Waste heat
so
Output = Input - Waste heat and efficiency = (input - waste heat)/output
Just press the calculator for the answer outcome XD
25% (apex) :)
25%, because three quarters of the input is lost to the environment
The useful work output is (100,000 - 75,000) = 25,000 joules.
Efficiency = (25,000/100,000) = 25%
If you subtract those two, you get the useful energy. Then divide the useful energy by the input, to get the efficiency.
APEX: 25%
25 percent
25%
56 kilo joules = 56,000 joules
103 joules
Yes. 5.42 calories equates to 22.692456 joules.
The needed heat is 47,65 Joules.
2520 Joules = (X)(4.180J/gC)(30C-10C) 2520J = 83.6X 30.14 grams of water.
25 percent
25 percent
25 percent
25%
Efficiency is measured in joules.
200,000-150,000= 50,000 25 %
400
The efficiency is 80%. To find the efficiency, 400/500 = 80%.
The efficiency is 80%. To find the efficiency, 400/500 = 80%.
If the input energy is 210 joules and the efficiency of the system is 30%,then the output energy is30% of 210 = (0.3 x 210) = 63 joules.
The machine efficiency is 35 percent (35/100).
The efficiency is 80%. To find the efficiency, 400/500 = 80%.