25%
Take Input - Waste = Difference
then D / I = Effeciency
so, 400000 - 300000 = 100000
and 100000 / 400000 = .25 or 25%
now ask the teacher next time...
Dont answer the question if you are going to get an attitude...
It depends on the efficiency of the coal conversion process. If the process is 30% efficient, then 70 joules would be lost to the environment for every 100 joules of chemical energy stored in coal.
There are 56,000 joules in 56 kilojoules. This is because there are 1,000 joules in a kilojoule.
Yes. 5.42 calories equates to 22.692456 joules.
The heat of solution for barium chloride is -61.7 kJ/mol. To convert this to joules, multiply by 1000 to get -61,700 J/mol.
An average apple contains about 52 calories, which is equivalent to approximately 217 joules.
The efficiency of the car's engine is calculated as the ratio of the useful work output to the total heat input. In this case, the useful work output is 500000 joules (2000000 J - 1500000 J) and the total heat input is 2000000 joules. Therefore, the efficiency is 500000 joules / 2000000 joules, which equals 0.25 or 25%.
The efficiency of the car's engine can be calculated using the formula: Efficiency = (Useful energy output / Total energy input) * 100%. In this case, the useful energy output is the heat used for work, which is (2000000 - 150000) Joules. Therefore, the efficiency would be ((2000000 - 150000) / 2000000) * 100% = 92.5%.
25%
25 percent
25 percent
The efficiency of the car's engine is calculated by dividing the useful energy output by the energy input. In this case, the useful energy output would be 5000 joules (20000 input - 15000 waste heat), thus the efficiency would be 5000/20000 = 0.25 or 25%.
Efficiency is measured in joules.
400
The efficiency of the street cleaner's engine is calculated by dividing the useful output (work done) by the input energy. In this case, the useful output is 150000J (work done) and the input energy is 200000J. The efficiency would be 150000J / 200000J = 0.75 or 75%.
The efficiency is 80%. To find the efficiency, 400/500 = 80%.
energy required to lift up 10kg=10x9.81x4=392.4 joule. enegy produced by the engine=500 joule efficiency=392.4/500=78.48%
The efficiency is 80%. To find the efficiency, 400/500 = 80%.