The efficiency of the car's engine is calculated as the ratio of the useful work output to the total heat input. In this case, the useful work output is 500000 joules (2000000 J - 1500000 J) and the total heat input is 2000000 joules. Therefore, the efficiency is 500000 joules / 2000000 joules, which equals 0.25 or 25%.
The efficiency of the car's engine can be calculated using the formula: Efficiency = (Useful energy output / Total energy input) * 100%. In this case, the useful energy output is the heat used for work, which is (2000000 - 150000) Joules. Therefore, the efficiency would be ((2000000 - 150000) / 2000000) * 100% = 92.5%.
The efficiency of the car's engine is calculated by dividing the useful energy output by the energy input. In this case, the useful energy output would be 5000 joules (20000 input - 15000 waste heat), thus the efficiency would be 5000/20000 = 0.25 or 25%.
To convert joules to kilojoules, divide the number of joules by 1000. For example, 1 kilojoule = 1000 joules, 5000 joules = 5 kilojoules.
A calorie is about 4.2 joules, therefore a kilocalorie is about 4200 joules. You can multiply by this number.
The efficiency of the street cleaner's engine is calculated by dividing the useful output (work done) by the input energy. In this case, the useful output is 150000J (work done) and the input energy is 200000J. The efficiency would be 150000J / 200000J = 0.75 or 75%.
The efficiency of the car's engine can be calculated using the formula: Efficiency = (Useful energy output / Total energy input) * 100%. In this case, the useful energy output is the heat used for work, which is (2000000 - 150000) Joules. Therefore, the efficiency would be ((2000000 - 150000) / 2000000) * 100% = 92.5%.
25%Take Input - Waste = Differencethen D / I = Effeciencyso, 400000 - 300000 = 100000and 100000 / 400000 = .25 or 25%now ask the teacher next time...Dont answer the question if you are going to get an attitude...
25%
25 percent
25 percent
60,000 joules per 10 seconds = 6,000 joules per second = 6,000 watts
The efficiency of the car's engine is calculated by dividing the useful energy output by the energy input. In this case, the useful energy output would be 5000 joules (20000 input - 15000 waste heat), thus the efficiency would be 5000/20000 = 0.25 or 25%.
400
There are 56,000 joules in 56 kilojoules. This is because there are 1,000 joules in a kilojoule.
To convert from kilo joules to joules you have divide by 1000 as 1 kilo joule is equal to 1000 joules. E.g. 2 kilo joules equals 2000 joules.
A petajoule is 1015 joules (Quadrillion joules)
4.18400 joules = 1 calorie, so 12.552 joules = 3 calories