The efficiency of the car's engine can be calculated using the formula: Efficiency = (Useful energy output / Total energy input) * 100%. In this case, the useful energy output is the heat used for work, which is (2000000 - 150000) Joules. Therefore, the efficiency would be ((2000000 - 150000) / 2000000) * 100% = 92.5%.
The efficiency of the car's engine is calculated as the ratio of the useful work output to the total heat input. In this case, the useful work output is 500000 joules (2000000 J - 1500000 J) and the total heat input is 2000000 joules. Therefore, the efficiency is 500000 joules / 2000000 joules, which equals 0.25 or 25%.
25 percent
The efficiency of the street cleaner's engine is calculated by dividing the useful output (work done) by the input energy. In this case, the useful output is 150000J (work done) and the input energy is 200000J. The efficiency would be 150000J / 200000J = 0.75 or 75%.
If the waste heat is 15 compared to the total heat input of 20 (ignoring the thousands) this means the heat doing useful work is 5, which represents 25 percent of the total input heat, so this is the efficiency. Waste heat in a car is the sum of the engine cooling losses and the exhaust losses, the rest is converted to mechanical energy which is useful. 25%
The efficiency of the car's engine is calculated by dividing the useful energy output by the energy input. In this case, the useful energy output would be 5000 joules (20000 input - 15000 waste heat), thus the efficiency would be 5000/20000 = 0.25 or 25%.
The efficiency of the car's engine is calculated as the ratio of the useful work output to the total heat input. In this case, the useful work output is 500000 joules (2000000 J - 1500000 J) and the total heat input is 2000000 joules. Therefore, the efficiency is 500000 joules / 2000000 joules, which equals 0.25 or 25%.
25 percent
The efficiency of the street cleaner's engine is calculated by dividing the useful output (work done) by the input energy. In this case, the useful output is 150000J (work done) and the input energy is 200000J. The efficiency would be 150000J / 200000J = 0.75 or 75%.
If the waste heat is 15 compared to the total heat input of 20 (ignoring the thousands) this means the heat doing useful work is 5, which represents 25 percent of the total input heat, so this is the efficiency. Waste heat in a car is the sum of the engine cooling losses and the exhaust losses, the rest is converted to mechanical energy which is useful. 25%
25%
25 percent
25 percent
25%Take Input - Waste = Differencethen D / I = Effeciencyso, 400000 - 300000 = 100000and 100000 / 400000 = .25 or 25%now ask the teacher next time...Dont answer the question if you are going to get an attitude...
The efficiency of the car's engine is calculated by dividing the useful energy output by the energy input. In this case, the useful energy output would be 5000 joules (20000 input - 15000 waste heat), thus the efficiency would be 5000/20000 = 0.25 or 25%.
Efficiency is measured in joules.
400
The efficiency is 80%. To find the efficiency, 400/500 = 80%.