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How would I find the electron configuration for carbon?
Carbon is the sixth element with a total of 6 electrons. In writing the electron configuration for carbon the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for C goes in the 2s orbital. The remaining two electrons will go in the 2p orbital. Therefore the C electron configuration will be 1s2 2s2 2p2.
Are the electrons next to the proton nucleus?
The nucleus is one the order of one fermion in diameter. The nearest electron orbital is on the order of more than a thousand fermions from the nucleus. To me, that pretty far away.
How do you arrange the electron in energy level in all atom?
Assuming the electron is in the lowest states and the atom is neutrally charged, it will fill an orbital before extending the next one. 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p H and He fill 1s as it holds two electrons. Li and Be fill 2s as it holds two electrons. B, C, N, O, F, and Ne will fill the 2p orbital as it holds 6 electrons (2p1, 2p2, and 2p3 orbitals). However, nitrogen will have one electron in each 2p1, 2p2, and 2p3 orbitals as an electron will not go two to an orbital until each orbital is filled. Neon completes the 2p orbital and is very stable (considered an inert gas--electrons are neither attracted nor want to leave the completed 2p orbital). Fluorine is the most electronegative element, as it wants to rip any electron it can to fill its 2p orbital. All noble gasses (right most on the periodic table) will complete a p-orbital. Periods 3-12 will fill a d-orbital. Lanthanoids and actinoids will fill the f-orbitals. So, for instance, Calcium (Ca) has an atomic number 20. You look up Ca on the periodic table. As it comes after He, it will have a 1p orbital filled. As it comes after Be, it will have a 2s orbital filled. As it comes after Ne, it will have a 2p orbital filled. And Ca will have a 3s orbital filled. Therefore, you note that Ca has electrons in the following orbitals: 1s, 2s, 2p, 3s. Another example is Fluorine (F), which would be: 1s, 2s, 2p1(2), 2p2(2), 2p3(1) where the parenthetical numbers note the number of electrons in each orbital.
Where would the element 119 be on the periodic table?
It would be the next Alkali Metal and would be placed under Francium.
What is the difference between excited hydrogen atom and any other atom?
Hydrogen atom = 1 proton 1 electron Hydrogen's 1 electron occupies the lowest energy level, 1s orbital. The atom is therefore in its "ground state". When a photon of correct frequency "collides" with a electron in hydrogen's 1s orbital the energy contained in the photon is transferred to the electron. The electron then gets added energy, so it is at a higher energy state. When it reaches this higher energy state the electron jumps to the next energy level and there it starts its new orbit. Hydrogen atom is now "excited" For any other atoms it is the same thing because all atoms can undergo excitation. The only difference between hydrogen's 1 electron and other atom's many electrons is WHICH ELECTRON will be "excited"
What noble gas has the smalleset electron cloud?
Helium. It only has 2 electrons in its one orbital or energy level. The next biggest would be Neon.
How would I find the electron configuration for carbon?
Carbon is the sixth element with a total of 6 electrons. In writing the electron configuration for carbon the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for C goes in the 2s orbital. The remaining two electrons will go in the 2p orbital. Therefore the C electron configuration will be 1s2 2s2 2p2.
How many electrons complete a full outer valence shell for sodium?
Atomic number of sodium is 11. So 11 electrons are there. First K shell could accomodate only 2. Now next L would have place for 8. So totally 10 electrons are firmy placed in the first two shells. Now remaining 1 electron would be in the third orbit M, that too in the s orbital. So sodium has 1 as valency. If suppose 8 electrons were there in the M shell, then s orbital 2, p orbital 6. But d orbital would be filled only after 4s orbital is filled with two electrons. So 8 electrons in s and p would make it less chemically reactive.
How does 2s orbital differ from a 1s orbital?
1s and 2s orbitals differ in that 2s orbitals lie farther away from the nucleus in the next principle energy level. Other than that, they occupy the same shape of orbital, spherical, as indicated by the s.
What atom is represented in the following orbital diagram 1s2s2p?
The next highest energy electron orbital after 3p is the 4s orbital, after which comes the 3d and then 4p orbitals.
Do the first orbital have to be full before placing electrons in the next orbital?
Yes
What symbol for the ion is formed if lithium loses 1 electron?
ok so you'll notice that lithium is on the second row of the periodic table, this means that its the next orbital hydrogen = 1s1 orbital helium = 2s1 orbital lithium = 2s1, 1s2 orbital removing the outter electron from lithium means that lithium has lost a minus charge and therefore must have a plus charge, this is called a cation. removing the electron also means now that there are no electrons in the s2 level do lithium is left with a 2s1 orbital, this is a very stable configuration and lithium wont loose any more electrons so your lithium ion will be nucleus with 3 protons 4 neutrons and 2 electrons with a plus charge to represent the loss of an electron
Are the electrons next to the proton nucleus?
The nucleus is one the order of one fermion in diameter. The nearest electron orbital is on the order of more than a thousand fermions from the nucleus. To me, that pretty far away.
When do d orbital start getting filled?
after the s orbital of the next highest energy level
When phosphorous is excited what will its electronic configuration be and Will the excited electron go to 4s orbital as per energy level diagram or 3d orbital and why?
In the case of excited phosphorus, the electron will bump up to the 3d level. This is the next closest location (in terms of energy) that the electron can go. Even though ground state phosphorus has no electrons in 3d, the atom can still access that sub-level because the principal quantum numbers for 3p (where its valence electrons are anyway) and 3d are the same.
How do you arrange the electron in energy level in all atom?
Assuming the electron is in the lowest states and the atom is neutrally charged, it will fill an orbital before extending the next one. 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p H and He fill 1s as it holds two electrons. Li and Be fill 2s as it holds two electrons. B, C, N, O, F, and Ne will fill the 2p orbital as it holds 6 electrons (2p1, 2p2, and 2p3 orbitals). However, nitrogen will have one electron in each 2p1, 2p2, and 2p3 orbitals as an electron will not go two to an orbital until each orbital is filled. Neon completes the 2p orbital and is very stable (considered an inert gas--electrons are neither attracted nor want to leave the completed 2p orbital). Fluorine is the most electronegative element, as it wants to rip any electron it can to fill its 2p orbital. All noble gasses (right most on the periodic table) will complete a p-orbital. Periods 3-12 will fill a d-orbital. Lanthanoids and actinoids will fill the f-orbitals. So, for instance, Calcium (Ca) has an atomic number 20. You look up Ca on the periodic table. As it comes after He, it will have a 1p orbital filled. As it comes after Be, it will have a 2s orbital filled. As it comes after Ne, it will have a 2p orbital filled. And Ca will have a 3s orbital filled. Therefore, you note that Ca has electrons in the following orbitals: 1s, 2s, 2p, 3s. Another example is Fluorine (F), which would be: 1s, 2s, 2p1(2), 2p2(2), 2p3(1) where the parenthetical numbers note the number of electrons in each orbital.
what is (Ne)3s2 3sp2?
(Ne)3s2 3p2 is an electron configuration notation that describes the arrangement of electrons in an atom or ion. The (Ne) in parentheses indicates that the electron configuration begins with the noble gas neon, which has the electron configuration 1s2 2s2 2p6. The 3s2 indicates that the next two electrons are in the 3s orbital, and the 3p2 indicates that the final two electrons are in two of the three 3p orbitals. The superscript 2 for each orbital indicates that there are two electrons in each orbital, following the Pauli exclusion principle, which states that no two electrons in an atom can have the same set of quantum numbers. The "sp" notation is not commonly used in electron configuration notation. It is more commonly used in hybridization notation to describe the hybridization of atomic orbitals in a molecule. In that context, "sp2" would indicate that one s orbital and two p orbitals have combined to form three hybrid orbitals, which are used to form sigma bonds with other atoms.
