Iron Sulphate + Sodium Hydroxide -> Sodium Sulphate (Na2SO4) and Iron Hydroxide (Fe(OH)2)
iron (II) sulfate and sodium hydroxide form a double displacement reaction with a precipitate. The products are Iron (II) hydroxide (s) and sodium sulfate (aq)
Fe2++2OH=Fe(OH)2
iron hydroxide plus ammonium sulfate
Sodium displaces the sulfate to make sodium sulfate; iron displaces the hydroxide to make ferrous hydroxide which becomes brown.
It produces a reddish precipitate of Iron(III) hydroxide and Sodium sulfate: Fe2(SO4)3 + NaOH ----> Fe(OH)3 + Na2SO4
FeSO4 + 2NaOH ---> Fe(OH)2 + Na2SO4
2Fe(SO4)3 + 6KOH ---> 2Fe(OH)3 + 3K2(SO4) iron 3 is +3, sulfate is -2, potasium is +1, and hydroxide is -1
You get Iron (III) Hydroxide and Sodium Nitrate. It is a double displacement chemical reaction...
Sodium displaces the sulfate to make sodium sulfate; iron displaces the hydroxide to make ferrous hydroxide which becomes brown.
FeSO4 + 2NaOH = Na2SO4(sodium sulphate] + Fe(OH)2 [iron(II) hydroxide / ferrous hydroxide].
Na2SO4 + Fe(OH)3
iron chloride + sodium hydroxide = sodium chloride +iron hydroxide
It produces a reddish precipitate of Iron(III) hydroxide and Sodium sulfate: Fe2(SO4)3 + NaOH ----> Fe(OH)3 + Na2SO4
FeSO4 + 2NaOH ---> Fe(OH)2 + Na2SO4
2Fe(SO4)3 + 6KOH ---> 2Fe(OH)3 + 3K2(SO4) iron 3 is +3, sulfate is -2, potasium is +1, and hydroxide is -1
Iron hydroxide (Fe(OH)2), Chlorine and Hydrogen.
= iron hydroxide plus sodium chloride
Iron oxide is with oxygen poopys
You get Iron (III) Hydroxide and Sodium Nitrate. It is a double displacement chemical reaction...
Iron Chloride + Sodium Hydroxide ------> Iron Hydroxide + Sodium Chloride Balanced reaction equations: FeCl3 + 3NaOH ------> Fe(OH)3 + 3NaCl or FeCl2 + 2NaOH ------> Fe(OH)2 + 2NaCl because iron can be either Iron(III)[Fe3+] or Iron(II)[Fe2+]