CH3COOH is Acetic Acid
Acid. It is made out of Carbon, Hydrogen, and Oxygen.
yES IT IS A VERY STRONG BASE (ONE OF THE STRONGEST)
CH3NH2 is a weak base, and works in the same way as ammonia.
CH3CO2- is acetate
if dissociated in water CH3CO2H is formed and since it has CO2H it is a carboxylic acid.
So its a weak acid
wallah ma b3raf mo met'akked y3ne ! :P
Base, because it ends in OH.
Its a salt
acid
Conjugated bases always have one proton less than its (conjugated) acids:So the conjugated base of carbonic acid ( H2CO3 ) is: hydrogen carbonate, formula HCO3-
Ethanoic acid is another name for acetic acid, which has the chemical formula CH3COOH. The reaction in solution is CH3COOH produces CH3CO2- + H+.
There is no such ion as H2CO3- However, the neutral molecule H2CO3 exists. Its conjugate base is the bicarbonate, or hydrogen carbonate ion: HCO3- The conjugate base of the bicarbonate ion is the carbonate ion: CO32-
2HCl(aq) + Ca(CH3CO2)2(aq) --> CaCl2(aq) + 2HCH3CO2(aq)Hydrochloric Acid + Calcium Acetate --> Calcium Chloride + Acetic Acid
thanks to you i solved mine...couldn't find ka of ch3co2h...but because pH=pKa+log([base]/[acid]) <----hasslbeck eqation. you know what pH your trying to get to 4.44 and pKa=-log(ka) = log(1.8*10^-5) which leaves 4.44=4.74+log([base]/[acid]) so.. -.30=log([base]/[acid]) so... ([base]/[acid])=10^-.3 so the ration is roughly .501187 good luck. chem sucks
The A- ion is the generic term for the conjugate base of an acid. The charge is balanced by an H+ ion. The identity and formula of this ion depends on the acid, for example, if the acid is acetic CH3CO2H acid, A- is the acetate ion or CH3CO2- If it is sulfuric acid (H2SO4) A- is the bisulfate ion HSO4-
The acetic acid is C2H4O2. It is often written has CH3CO2 to distinguish it from its isomers.
Conjugated bases always have one proton less than its (conjugated) acids:So the conjugated base of carbonic acid ( H2CO3 ) is: hydrogen carbonate, formula HCO3-
Vinegar is an acid because it contains acetic acid, which produces hydrogen ions when dissolved in water. CH3CO2H --> CH3CO2- + H+
Ethanoic acid is another name for acetic acid, which has the chemical formula CH3COOH. The reaction in solution is CH3COOH produces CH3CO2- + H+.
There is no such ion as H2CO3- However, the neutral molecule H2CO3 exists. Its conjugate base is the bicarbonate, or hydrogen carbonate ion: HCO3- The conjugate base of the bicarbonate ion is the carbonate ion: CO32-
2HCl(aq) + Ca(CH3CO2)2(aq) --> CaCl2(aq) + 2HCH3CO2(aq)Hydrochloric Acid + Calcium Acetate --> Calcium Chloride + Acetic Acid
There are many acids with many different chemical formulas. Here are a few common ones: Sulfuric acid: H2SO4 Acetic acid: CH3CO2 Carbonic acid: H2CO3 Hydrochloric acid: HCl Oxalic acid: H2C2O4 Nitric acid: HNO3
thanks to you i solved mine...couldn't find ka of ch3co2h...but because pH=pKa+log([base]/[acid]) <----hasslbeck eqation. you know what pH your trying to get to 4.44 and pKa=-log(ka) = log(1.8*10^-5) which leaves 4.44=4.74+log([base]/[acid]) so.. -.30=log([base]/[acid]) so... ([base]/[acid])=10^-.3 so the ration is roughly .501187 good luck. chem sucks
An acid can turn into a base if you mix a much stronger base with it! That way the base acid overpowers the acid and makes the acid a base!
Acid + base conjugate base + conjugate acid
It is a base It is a base It is a base