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How are H3O plus and OH- related?

Updated: 8/10/2023
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11y ago

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By equilibrium only in water:

Ionconcentration product = KW ,

meaning:

[H30+] * [OH-] = 1.0*10-14 (at 25oC)

H30+(aq) + OH-(aq) <==>> H2O(l)
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11y ago
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14y ago

It is the aqueous solution of Acetic acid.

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13y ago

H3O is a strong acid.

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14y ago

H30+(aq) + OH-(aq) ----> H2O(l)

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Q: How are H3O plus and OH- related?
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What are the concentrations of H3O plus and OH in pure water?

H3O= 0.9 mol/dm3 OH=1.2 mol/dm3


Copper plus water equals?

Cu+ H2O [OH + H3O= 2H2O]Copper plus more than one water = [CuOH + H3O]


Does Kw show the interdependence of the H3O plus and OH- in aqueous solutions?

Yes.


What is the OH- of H3O plus of 1x10-5?

It must be 1 x 10-9


What statements correctly describes the hydronium-hydroxide balance in the given solution?

In neutral solutions, [H3O+] = [H2O].In bases, [OH-] = [H3O+].In bases, [OH-] is greater than [H3O+].In acids, [OH-] is greater than [H3O+].In bases, [OH-] is less than [H3O+].


What substance is the conjugate acid in the reaction HBr plus H2O H3O plus plus Br?

H3o+


The ph of lemon juice at 298 k is found to be 2.32 what is the concentration oh H3O plus ions in the solution?

If the PH of lemon juice at 298 k is found to be 2.32, the concentration of H3O plus ions in the solution would be 0.5 M.


Is H3O plus behaving as an acid or base in the following reaction H3PO4 plus H2O H2PO4- plus H3O plus?

In this reaction H3O+ is the conjugate acid. The original acid in this reaction is H3PO4


Is h3o plus acid or base?

H3O is a strong acid.


Prove that Kw equals product of Ka and Kb for an acid-base pair in water?

dissociation of acid in water: A + H2O &lt;-&gt; A- + H3O+ with dissociation constant Ka = [A-][H3O+]/[A][H2O] = [A-][H3O+]/[A]. dissociation of base in water: B + H2O &lt;-&gt; HB+ + OH- with dissociation constant Kb = [HB+][OH-]/[B][H2O] = [HB+][OH-]/[B] dissociation of water in itself: 2H2O &lt;-&gt; H3O+ + OH- with dissociation constant Kw = [H3O+][OH-]/[H2O]^2 = [H3O+][OH-] where [H2O] has been ommitted because it is a pure liquid. substituting relations for Ka and Kb into Kw gives: Kw = [H3O+][OH-] = (Ka[A]/[A-])(Kb[B]/[HB+]) = KaKb where [A] = [HB+] and [B] = [A-].


What are the H3O plus and OH- for a solution with the following pH value 10.0?

pH=10, means the concentration of OH- ions is 0.0001 M and concentration of H+ ions is 0.0000000001M


Given that you have a H3O concentration of 0.0034 M what is the OH-?

[H3O+][OH-] = Kw = 1x10^-14[OH-] = 1x10^-14/0.0034 = 1x10^-14/3.4x10^-3[OH-] = 2.9x10^-12 M