Elements prefer to live in their natural forms.N2 and O2 are more stable than NO.Added:Air is a mixture of N2 and O2 molecules, where NO is a compound, chemically formed by reaction: N2 + O2 --> 2 NO. This reaction does not take place at normal conditions as in the air around us.
for o2 -bp==2 for n2 bp =3
It is an element. Since any temperature is "natural", the physical state is meaningless. It can be anything from a Bose-Einstein condensate (unlocalizeable), a solid, a liquid, a gas, or a plasma... and be "natural" for that temperature. At standard temperure and pressure, it is a very stable diatomic gas (N2). Nitrogen's natural stage is N2 gas. It is diatomic and can only exist with 2 nitrogen molecules, so it must be N2 not N.
Three: The reaction equation is N2 + 3 H2 -> 2 NH3
N2 + 3H2 ==> 2NH3moles N2 = 1.20 molesmoles NH3 formed = 1.20 moles N2 x 2 moles NH3/1 moles N2 = 2.40 moles NH3mass NH3 = 2.40 moles x 17 g/mole = 40.8 g NH3
Three pairs of electrons.
Elements prefer to live in their natural forms.N2 and O2 are more stable than NO.Added:Air is a mixture of N2 and O2 molecules, where NO is a compound, chemically formed by reaction: N2 + O2 --> 2 NO. This reaction does not take place at normal conditions as in the air around us.
n2-3n+2
(N2) + 3(H2) = 2(NH3)
n2 + n2 = 2 n2
n2-1 and n2-4 are trivial cases because of n2-m2=(n-m)(n+m). So the only prime of the form n2-1 is 3 and of the form n2-4 is 5.
More NO would form
3H2 + N2 --> 2NH3This is the Haber process which makes ammonia (NH3)
You have :N2 + O2 -----> 2NOmoles NO = ( 2 mols N2 reacted ) ( 2 mol NO / mol N2 reacted )moles NO = 4 moles NOmass NO = ( 4 mol NO ) ( 30 g NO / mol NO ) = 120 g NO
for o2 -bp==2 for n2 bp =3
N2 is a very stable, nonreactive , non-polar gas so is almost insoluble in water.
n2 + 11n + 18 = n2 + 2n + 9n + 18 = n(n+2) + 9(n+2) = (n+9)*(n+2)