No
No, a negligible amount may dissolve in methyl alcohol and ethyl alcohol.
you start with the 5.00g PbCl2 then use a conversion factor for the molar mass of pbcl2 (1mol pbcl2/278.1gpbcl2) now from mol pbcl2 use another conversion factor to get g cl2 (70.90gCl2/1 mol PbCl2) do the math and you wind up with 1.27 g Cl2
Mercury (II) chloride is soluble, but Mercury (I) (mercurous) chloride is insoluble. The formula of the first compound is HgCl2, and mercurous chloride is Hg2Cl2. Also, lead chloride (PbCl2) and Silver chloride (AgCl) is insoluble. All other chloride solutions are soluble.
Zn + PbCl2 --> Pb + ZnCl2
No
KCl is soluble. PbCl2 is insoluble. Test their solubilities in water.
no,because it has a cloride ion and all clorides are soluble
No, a negligible amount may dissolve in methyl alcohol and ethyl alcohol.
PbBr2 is only slightly soluble in water, but more so than PbCl2, so if you had to write the equation it would be2LiCl(aq) + PbBr2(aq) ==> 2LiBr(aq) + PbCl2(s)
Its aqueous because all chloride compounds are soluble except AgCl PbCl2 and Hg2Cl2.
you start with the 5.00g PbCl2 then use a conversion factor for the molar mass of pbcl2 (1mol pbcl2/278.1gpbcl2) now from mol pbcl2 use another conversion factor to get g cl2 (70.90gCl2/1 mol PbCl2) do the math and you wind up with 1.27 g Cl2
Mercury (II) chloride is soluble, but Mercury (I) (mercurous) chloride is insoluble. The formula of the first compound is HgCl2, and mercurous chloride is Hg2Cl2. Also, lead chloride (PbCl2) and Silver chloride (AgCl) is insoluble. All other chloride solutions are soluble.
Zn + PbCl2 --> Pb + ZnCl2
CrCl3 is insoluble, unless it is in its hydrated form CrCl3*6H2O
Pb(OH)2 + 2HCl --> PbCl2 + 2H2O
It is very slightly soluble in water.In a saturated solution:[Pb2+] = 1.2x10-2 mol/L[Br-] = 2.4x10-2 mol/Lbecause [Pb2+]*[Br-]2 = Ks = 6.3*10-6 and [Br-] = 2*[Pb2+]