0
What else can I help you with?
What mass of KCl would be needed to form a saturated solution if the KCl was dissolved in 200 g of water at 80 C?
The solubility of KCl in water at 80°C is approximately 380 g/L. To form a saturated solution, you would need to dissolve 380 g of KCl in 1 L (1000 g) of water. Since you are using 200 g of water, you would need 76 g of KCl to form a saturated solution.
Is KCl insoluble?
No. Potassium chloride (KCl) is soluble in water.
How many grams of KCl to make 50 mL of 2.45 M KCl?
To calculate the grams of KCl needed, first calculate the moles of KCl required using the molarity formula. Then, convert moles to grams using the molar mass of KCl, which is approximately 74.55 g/mol.
How many grams of KCl remain in solution at 20 degrees celsius when a solution containing 80g of KCl in 200g of water at 50 degrees Celsius is cooled to 20 degrees Celsius?
To find the amount of KCl that remains in solution at 20 degrees Celsius, you can use the principle of solubility. Calculate the maximum amount of KCl that can dissolve in 200g of water at 20 degrees Celsius using a solubility chart. Once you have this value, compare it to the initial 80g of KCl to determine how much remains in solution after cooling.
Is KCl a solute or a solvent?
Potassium chloride does form an aqueous solution when dissolved in water.
What is the net ionic equation for KCl (aq) plus Pb(NO3)2 (aq) --- and gt KNO3 (aq) plus PbCl2 (s)?
The net ionic equation for the reaction between KCl(aq) and Pb(NO3)2(aq) to form KNO3(aq) and PbCl2(s) is: 2K^+(aq) + 2NO3^-(aq) + Pb^2+(aq) + 2Cl^-(aq) -> 2K^+(aq) + 2NO3^-(aq) + PbCl2(s)
What produces a chemical change?
One example is the reaction between the aqueous solutions lead nitrate, Pb(NO3)2 and potassium chloride, KCl. They react to form solid (a precipitate) lead chloride, PbCl2, and aqueous potassium nitrate, KNO3. The balanced equation is Pb(NO3)2(aq) + KCl(aq) ---> PbCl2(s) + KNO3(aq)
What mass of KCl would be needed to form a saturated solution if the KCl was dissolved in 200 g of water at 80 C?
The solubility of KCl in water at 80°C is approximately 380 g/L. To form a saturated solution, you would need to dissolve 380 g of KCl in 1 L (1000 g) of water. Since you are using 200 g of water, you would need 76 g of KCl to form a saturated solution.
Which mass of kcl would you add to water to make a 2.00 l of a 1.20 m solution?
To prepare a 1.20 M potassium chloride (KCl) solution in 2.00 L of water, you would need to add 144 grams of KCl. This calculation can be determined using the formula: moles = Molarity x volume (in liters). Then, convert moles to grams using the molar mass of KCl.
Is KCl insoluble?
No. Potassium chloride (KCl) is soluble in water.
Is KCl soluble or insoluble?
KCl is highly soluble in water and some other solvents.
What precipitate will result when the solutions PbNO are mixed with KCi?
When solutions of lead(II) nitrate (Pb(NO3)2) and potassium chloride (KCl) are mixed, a precipitate of lead(II) chloride (PbCl2) will form. This is because lead(II) chloride is insoluble in water and will precipitate out of the solution.
How many grams of KCl to make 50 mL of 2.45 M KCl?
To calculate the grams of KCl needed, first calculate the moles of KCl required using the molarity formula. Then, convert moles to grams using the molar mass of KCl, which is approximately 74.55 g/mol.
How many grams of KCl remain in solution at 20 degrees celsius when a solution containing 80g of KCl in 200g of water at 50 degrees Celsius is cooled to 20 degrees Celsius?
To find the amount of KCl that remains in solution at 20 degrees Celsius, you can use the principle of solubility. Calculate the maximum amount of KCl that can dissolve in 200g of water at 20 degrees Celsius using a solubility chart. Once you have this value, compare it to the initial 80g of KCl to determine how much remains in solution after cooling.
Is KCl a solute or a solvent?
Potassium chloride does form an aqueous solution when dissolved in water.
What color is KCl in water?
the solution of KCl looks like a clear water with little tint of gray swirls
How can you prepare 0.01M KCL solution in 1liter?
To prepare a 0.01M KCl (potassium chloride) solution in 1 liter, you would need to dissolve 0.74 grams of KCl in enough water to make 1 liter of solution. This can be calculated using the formula: moles = Molarity x Volume (in liters) x Molecular weight of KCl.
